What is the value of x? sin(x+37)°=cos(2x+8)° Enter your answer in the box. x =

Answer:

The answer is J

Step-by-step explanation:

If you start from Quinn's location (8,7), and move south 3 units, you get to (8,4). Then you move to the west 4 units and that gets you to (4,4).

hope this helped! :)

Given,A school janitor has mopped 1/3 of a classroom in 5 minutes.We have to find the rate at which he is mopping.Using the concept of unitary method,Rate of mopping 1 classroom in 5 × 3 = 15 minutes= 1/15 of a classroom in 1 minute.Rate of mopping 1/3 classroom in 5 minutes = (1/3) ÷ 5= 1/15 classroom per minuteHence, the required rate at which he is mopping is 1/15 classroom per minute.

Answer: 1/15.

To determine the rate at which the janitor is mopping, we can calculate the fraction of the classroom mopped per minute.

Given that the janitor mopped 1/3 of the classroom in 5 minutes, we can express this as:

(1/3) classroom / 5 minutes

To simplify this fraction, we divide the numerator and denominator by the greatest common divisor, which is 1:

(1/3) classroom / (5/1) minutes = (1/3) classroom × (1/5) minutes

Multiplying the numerators and the denominators gives us:

1 classroom × 1 minute / 3 × 5

Simplifying further:

1 classroom × 1 minute / 15

Therefore, the rate at which the janitor is mopping is 1/15 classrooms per minute.

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The given information is that the janitor mopped 1/3 of a classroom in 5 minutes. We have to find out at what rate is he mopping.

The rate of mopping is 1/15 classrooms per minute.

Let's try to solve the problem below. The given fraction is 1/3 of a classroom that was mopped in 5 minutes. We need to find the rate of mopping which can be calculated by dividing the fraction of the classroom mopped by the time it took to mop it. The rate of mopping can be found by performing the following calculation:

Rate of mopping = Fraction of the classroom mopped/Time taken to mop

= 1/3/5

= 1/15

So the rate of mopping is 1/15 classrooms per minute. This is the simplified answer.

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The z-score for a student who received a score of 90 on the entrance exam is 1.6.

The z-score for a student who received a score of 90 on the entrance exam, with a mean of 82 and a standard deviation of 5, can be calculated as follows:

Plugging in the values:

Simplifying:

Calculating:

Therefore, the z-score for the student who received a score of 90 on the exam is 1.6.

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Answer:

The answers are in the attachment above

good day mate

Angle ∠B is a right-angle then the measure of angle ∠A is 43.6 degrees and the measure of angle ∠C is 46.4 degrees.

It is a type of triangle in which one angle is 90 degrees and it follows the Pythagoras theorem and we can use the trigonometry function. The Pythagoras is the sum of the square of two sides is equal to the square of the longest side.

The triangle ΔABC is given.

The angle ∠B is a 90°.

Then the value of the angle ∠C will be

[tex]\rm C = \sin ^{-1} \dfrac{21}{29}\\\\C = 46.40^o[/tex]

Then the value of the angle ∠A will be

     ∠A + ∠C = 90°

∠A + 46.40° = 90°

              ∠A = 43.6°

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Answer:

A

Step-by-step explanation:

Answer:

Step-by-step explanation:

Monday: c and p

Tuesday: 2c+p

Wednesday: 2c+p/2

Thursday: 6c+3p/2

Friday: (2c-12)+(p/2+5)

Adding them all up, you get, for Monday-Friday:  (13c-12)+(9p/2+5)

I'm not sure how to explain this to you though, you just follow the directions they gave, to multiply and subtract.

Hope this is helpful!

Answer:

0.5, 0, -1/4, -1

Answer:

The tree is 8 foot long

hope this helps

good day mate

Answer:

8

Step-by-step explanation:

12:6 = x:4

2:1 = x:4

x=8

Answer:

13 + x ≤ 22

x ≤ 9

Step-by-step explanation:

Total players = 22

Players available = 13

Players remaining = x

The inequality can be written as:

Players available + Players remaining ≤ Total players

13 + x ≤ 22

x ≤ 22 - 13

x ≤ 9

Answer:

who?

Step-by-step explanation:

Answer:

you got this

Step-by-step explanation:

I believe in you

Answer:

After 8 hrs both candles would've burned out completely, so they'll, more or less, be at the same height.

Given: Nationwide, 40% of college seniors say that if they could start their college education over, they would have selected a different major. A student researcher in the education department selected a random sample of 50 seniors at Harvard and asked them if they the same question.

a. Mean is 0.40 (40%) and Standard deviation = 0.0775.

b. we cannot conclude that the percent that would have selected a different major is different at Harvard than the national average.

a. Assuming the percent of seniors at Harvard that would select a different major is consistent with the national percentage, X (the number in 50 randomly selected seniors that would select a different major at Harvard) would have an approximately normal distribution.

The mean would be the same as the population mean, which is 0.40 (40%).

The standard deviation would be calculated using the formula given below:

Standard deviation = sqrt[(p(1-p))/n], Where, p = population proportion (0.40), n = sample size (50).

Standard deviation = sqrt[(0.40 x 0.60)/50]

Standard deviation ≈ 0.0775

b. To determine if the percent that would have selected a different major is different at Harvard than the national average, we need to perform a hypothesis test.

Hypotheses:H_0: p = 0.40 (The proportion of seniors at Harvard who would have selected a different major is the same as the national percentage.)

H_a: p ≠ 0.40 (The proportion of seniors at Harvard who would have selected a different major is different from the national percentage.)

Since the sample size (50) is greater than 30 and the population standard deviation is unknown, we can use the z-test to test the hypothesis.

The formula for the test statistic is given below:

z = (p - P)/sqrt[(P(1 - P))/n], Where, p = sample proportion, P = population proportion, n = sample size.

z = (12/50 - 0.40)/sqrt[(0.40 x 0.60)/50]

z ≈ -1.84

Using a significance level of α = 0.05 and a two-tailed test, the critical values of z are ±1.96.

Since the calculated z-value (-1.84) is less than the critical value (-1.96), we fail to reject the null hypothesis.

We do not have sufficient evidence to conclude that the proportion of seniors at Harvard who would have selected a different major is different from the national percentage.

Therefore, we cannot conclude that the percent that would have selected a different major is different at Harvard than the national average.

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Answer:

3600 Liters

Step-by-step explanation:

The given rate is 2L and we have to find how much water will flow in 1/2 hours at the same rate

1/2 hour is the same thing as 30 mins

multiply by 60 to convert minutes to seconds

[tex]3omin * \frac{60sec}{1min} = 1800 s[/tex]

since the rate is 2L per second we multiply 1800 by 2 and get 3600 Liters

Answer:

[tex](4,-20)[/tex]

Step-by-step explanation:

Let [tex]P(x,y),\,Q(u,v)[/tex] be two points then midpoint of [tex]PQ[/tex] is given by [tex](\frac{x+u}{2},\frac{y+v}{2})[/tex]

Put midpoint as [tex](6,-10)[/tex] and [tex](u,v)=(8,0)[/tex]

Therefore,

[tex](\frac{x+u}{2},\frac{y+v}{2})=(6,-10)\\\\(\frac{x+8}{2},\frac{y+0}{2})=(6,-10)\\\\\frac{x+8}{2}=6,\,\frac{y}{2}=-10\\\\x+8=12,\,y=-20\\x=12-8,\,y=-20\\x=4,\,y=-20[/tex]

So, the other point is [tex](4,-20)[/tex]

The critical z value for a confidence level of 85% is approximately 1.44.

To understand this better, let's delve into the concept of confidence level. A confidence level is a measure of the uncertainty or margin of error associated with an estimation. In this case, we are given a confidence level of 85%, which means that we want to be 85% confident that the true population parameter falls within a specific range.

To find the critical z value, we need to determine the z value that leaves a certain percentage in the tails of the standard normal distribution. Since the confidence level is 85%, we divide this value by 2 to get a/2, which is 0.85/2 = 0.425. This value corresponds to the area under the curve in one tail of the distribution.

Using a standard normal distribution table or a statistical software, we can find the z value that corresponds to a cumulative probability of 0.425. The closest z value to this probability is approximately 1.44. Therefore, the critical z value for a confidence level of 85% is approximately 1.44.

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Answer:

Step-by-step explanation:

We know that there are 24 white marbles in the starting.

a. How many were not chosen. => 1/6 of the white marbles.

1/6 * 24 = 4 marbles were not chosen.

b. 24 - 4 = 20 marbles were chosen

c. Not enough Info

Answer:

4,20,not enough info

Step-by-step explanation:

Answer:

2/b

Step-by-step explanation:

9 yards

The required answer is  sec θ = -√2.

Explanation:-

Part 1: Given cosine of theta is equal to radical 3 over 2 on the domain [0,[infinity]).

To determine three possible angles θ,  the cosine inverse function which is a cos and since cosine function is positive in the first and second quadrant. Therefore  conclude that, cosine function of θ = radical 3 over 2 implies that θ could be 30 degrees or 330 degrees or 390 degrees. So, θ = {30, 330, 390}.Part 2:To convert 495° to radians, multiply by π/180°.495° * π/180° = 11π/4To find sec θ, we use the reciprocal of the cosine function which is sec.

Therefore, sec θ = 1/cos θ.To find cos 11π/4,  the reference angle, which is 3π/4. Cosine is negative in the third quadrant so the final result is sec θ = -√2.

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Answer:

Step-by-step explanation:

the area of the rectangle is : -7y² ( -2y^4+y²-1)

14y^6-7y^4+7y²   unit

Answer:

The answer is a...............

Answer:

The discount was 24%.

Step-by-step explanation:

24% of 50 is 12.

(a) The inverse matrix A⁻¹ is:

| -9/2   5/2 |

|  1     -1 |

(b) The solution to the system is x = -9/2 and y = 1. z is undetermined.

(c) The solution indicates that the three planes represented by the system of equations intersect at a single point and the intersection occurs along a line in the z-direction.

(a) The coefficient matrix, A, is given by:

A = | 2  10   42 |

     | 4  18   10 |

We can use matrix inversion. A matrix is invertible if its determinant is non-zero. Let's calculate the determinant of matrix A:

det(A) = (2 * 18) - (10 * 4) = 36 - 40 = -4

Since the determinant is non-zero (-4 ≠ 0), the matrix A is invertible. Now, we can find the inverse of A:

A⁻¹ = (1/det(A)) * adj(A)

Where adj(A) denotes the adjugate of matrix A. To calculate the adjugate, we need to find the cofactor matrix of A and then take its transpose:

Cofactor matrix of A:

| 18   -4 |

| -10   2 |

Transpose of the cofactor matrix:

| 18  -10 |

| -4    2 |

Now, divide the transpose by the determinant:

A⁻¹ = (1/-4) * | 18  -10 |

                 | -4    2 |

Simplifying:

A⁻¹ = | -9/2   5/2 |

        |  1     -1 |

Therefore, the inverse matrix A⁻¹ is:

| -9/2   5/2 |

|  1     -1 |

(b) We have the equation AX = B, where X is the column vector of variables (x, y, z), A is the coefficient matrix, and B is the column vector of constants.

The coefficient matrix A is:

A = | 2  10   42 |

     | 4  18   10 |

The column vector B is:

B = | 1 |

      | 0 |

Now, we can solve for X using A-1:

X = A⁻¹ * B

Substituting the values:

X = | -9/2   5/2 | * | 1 |

          | 1    -1 |      | 0 |

Multiplying the matrices:

X = | (-9/2 * 1) + (5/2 * 0) |

        | (1 * 1) + (-1 * 0) |

Simplifying:

X = | -9/2 |

        |   1   |

Therefore, the solution to the system is x = -9/2 and y = 1. The value of z is not determined from this calculation.

(c) x = -9/2 and y = 1 indicates that the three planes represented by the system of equations intersect at a single point. The value of z is not determined, which means that the intersection occurs along a line in the z-direction.

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Answer:

1. D

2. B

3. C

4. A

Step-by-step explanation:

just know when the sentence says "each" or "per" next to a number, there need to be an x next to it.

In other words, I kinda just winged it :P

Answer:

37 pounds of apples.

Step-by-step explanation:

you add together the amount of apples that both people have gathered, which in this case would be 33+4 which makes 37, so your answer would be 37 apples.

Answer:

5

Step-by-step explanation:

The winnings are in G.P. : 1, 2, 4, ..... till 10 toss.

[tex]$a_n = 1 \times 2^{n-1}\ \ \ \forall \ n = 1,2,3,4,....,10$[/tex]

[tex]$a_n$[/tex] denotes the winnings on the [tex]$n^{th}$[/tex] toss.

The probability of earning amount [tex]$a_n$[/tex] on the [tex]$n^{th}$[/tex] toss is = [tex]$\left(\frac{1}{2}\right)^n$[/tex]

∴ [tex]$E(X) = \sum_{n=1}^{10} \ a_n \times \left(\frac{1}{2}\right)^n $[/tex]

            [tex]$=\sum_{n=1}^{10} \ 1 \times \frac{2^{n-1}}{2^n} $[/tex]

           [tex]$=\sum_{n=1}^{10} \ \frac{1}{2}$[/tex]

Sum of the 1st n terms of the A.P. is :

[tex]$=\frac{n}{2}[2a+(n-1)d] $[/tex]

[tex]$=\frac{10}{2}[2\times \frac{1}{2}+(10-1)\times 0] $[/tex]

= 5

Therefore, E(X) = 5

Hence the expected value of the game is 5

a. The variance of the data set is 279.111 and the standard deviation is 16.707.

b. Adding an expensive cheese increases the mean to 55.9 and the standard deviation to 48.53.

a. To compute the variance and standard deviation for the given data set, we can use the following formulas:

Variance (s²) = [(Σx²) - (Σx)² / n] - 1

Standard Deviation (s) = √(Variance)

Using the given data set: 29, 62, 37, 41, 70, 82, 47, 52, 49

Step 1: Calculate the mean (x) of the data set.

Mean (x) = (Σx) / n

Σx = 29 + 62 + 37 + 41 + 70 + 82 + 47 + 52 + 49 = 409

n = 9 (number of data points)

Mean (x) = 409 / 9 = 45.44 (rounded to two decimal places)

Step 2: Calculate the sum of squares (Σx²) for the data set.

Σx² = 29² + 62² + 37² + 41² + 70² + 82² + 47² + 52² + 49² = 151509

Step 3: Substitute the values into the variance formula and calculate the variance.

Variance (s²) = [(Σx²) - (Σx)² / n] - 1

Variance (s²) = (151509 - (409)² / 9) / (9 - 1) = 279.111 (rounded to three decimal places)

Step 4: Calculate the standard deviation by taking the square root of the variance.

Standard Deviation (s) = √(Variance)

Standard Deviation (s) = √279.111 = 16.707 (rounded to three decimal places)

b. If a very expensive cheese with a cost per slice of 150 cents was added to the data set, the values of the mean and standard deviation would change. To find the new mean and standard deviation, we need to incorporate the additional data point and recalculate.

New Σx = Σx + 150 = 409 + 150 = 559 (updated sum of the data points)

New n = n + 1 = 9 + 1 = 10 (updated number of data points)

New Mean (x) = New Σx / New n = 559 / 10 = 55.9 (rounded to one decimal place)

The addition of the expensive cheese increased the mean.

To calculate the new variance and standard deviation, we follow the same steps as in part a using the updated Σx and n values:

New Σx² = Σx² + (150)² = 151509 + 22500 = 174009

New Variance (s²) = [(New Σx²) - (New Σx)² / New n] - 1 = (174009 - (559)² / 10) / (10 - 1) = 2355 (rounded to three decimal places)

New Standard Deviation (s) = √New Variance = √2355 = 48.53 (rounded to two decimal places)

Therefore, the addition of the expensive cheese increased both the mean and the standard deviation of the data set.

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Answer:

1. false

2. false

3. true

Step-by-step explanation:

A survey of 150 college students was done to find out what elective course they were taking Lot A the set of those taking ort, B the set of those taking basketweaving, and C - the set of those taking canoeing. The study revealed the following information A-45 IAN B = 12 181 55 ANC-15 C-40 BC-2 Anno 2  

Based on the given information, we can calculate the number of students who were not taking any of the elective courses.

Let's break down the information provided:

A: The set of students taking Art elective = 45

B: The set of students taking Basket weaving elective = 12

C: The set of students taking Canoeing elective = 40

A ∩ B: The set of students taking both Art and Basket weaving electives = 2

A ∩ C: The set of students taking both Art and Canoeing electives = 15

B ∩ C: The set of students taking both Basket weaving and Canoeing electives = 0 (not specified)

A ∩ B ∩ C: The set of students taking all three electives = 2

To find the number of students who were not taking any of these electives, we need to subtract the total number of students taking at least one elective from the total number of students surveyed.

Total students surveyed = 150

Students taking at least one elective = A ∪ B ∪ C

Students taking at least one elective = A + B + C - (A ∩ B) - (A ∩ C) - (B ∩ C) + (A ∩ B ∩ C)

Students taking at least one elective = 45 + 12 + 40 - 2 - 15 - 0 + 2

Students taking at least one elective = 82

Students not taking any of these electives = Total students surveyed - Students taking at least one elective

Students not taking any of these electives = 150 - 82

Students not taking any of these electives = 68

Therefore, there were 68 students who were not taking any of the elective courses using set theory.

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