what is the wavelength of a wave with the frequency of 330 Hz and a speed of 343 m/s

Answers

Answer 1

Answer:

The wavelength of a wave with the frequency of 330hz and a speed of 343m/s would be 1.04m

Explanation:

You can get the wavelength of a wave by dividing the speed of the wave by its frequency, which in this case would be:

343/300, which as a decimal number, it'd be 1.04.

I hope I helped you, and a "Brainliest" is always appreciated! ☺


Related Questions

The fictional rocket ship Adventure is measured to be 50 m long by the ship's captain inside the rocket.When the rocket moves past a space dock at 0.5c, space-dock personnel measure the rocket ship to be 43.3 m long. Part A The rocket ship Adventure travels to a star many light-years away, then turns around and returns at the same speed. When it returns to the space dock, who would have aged less: the space-dock personnel or ship's captain?

Answers

Complete question:

Part A:) The fictional rocket ship Adventure is measured to be 50 m long by the ship's captain inside the rocket.When the rocket moves past a space dock at 0.5c , space-dock personnel measure the rocket ship to be 43.3 m long. The rocket ship Adventure travels to a star many light-years away, then turns around and returns at the same speed. When it returns to the space dock, who would have aged less: the space-dock personnel or ship's captain?

Part B: What is the momentum of a proton traveling at 0.62 c ?

Answer

a)Who would have aged less=The Captain would have aged less

b) [tex]p=3.96*10^{-19}kgm/s[/tex]

Explanation:

From the question we are told that

Length measured by captain [tex]l_c=50m[/tex]

Speed of rocket past tje space dock [tex]V=0.5c[/tex]

Length measured by space-dock personnel [tex]l_c=43.3m[/tex]

a)

Generally time moves slower when moving at speed of light, due to time dilation or variation.

Who would have aged less=The Captain would have aged less

b)

Generally the equation for Relativistic Momentum  is mathematically given as

[tex]p=\frac{m*v}{1 - v^2/c^2}[/tex]

[tex]p=\frac{1.67*10^2-27*0.62*3.0*10^8)}{\sqrt{ 1 -0.6^2}}[/tex]

[tex]p=3.96*10^{-19}kgm/s[/tex]

Which of the following statements about waves is NOT true?

Amplitude is related to the amount of energy in a wave.


Frequency is related to the number of wave cycles per unit of time.


Wavelength is the distance from the wave crest to the wave trough.


Waves transfer energy (sometimes in the form of vibrations).

Wave amplitude it the distance from the rest position to the crest or trough

Answers

This statement is not true:

"Wavelength is the distance from the wave crest to the wave trough."

The others listed are true.

A light bulb has 0.25 A of current using a voltage of 120 V. What is the power rating for this bulb?

Answers

We can't tell what RATING is printed on the package of bulbs, but right now, the bulb is dissipating IxE= 30 watts of heat and light.

Consider the following situation, in which a compass is influenced by not only the force of Earth's magnetic field, but also an additional applied force.

1. Which of the following is true of the angle of deflection of the compass relative to FEarth if FEarth > FApplied?

a. The angle of deflection will be exactly 45°
b. The angle of deflection will be greater than 90°
c. The angle of deflection will be less than 45°
d. The angle of deflection will be exactly 0°
e. The angle of deflection will be greater than 45° but less than 90°

2. Which of the following is true of the angle of deflection of the compass relative to FEarth if FEarth < FApplied?

a. The angle of deflection will be exactly 45°
b. The angle of deflection will be greater than 90°
c. The angle of deflection will be less than 45°
d. The angle of deflection will be exactly 0°
e. The angle of deflection will be greater than 45° but less than 90°

Answers

Answer:

1) The angle of deflection will be less than 45° ( C )

2)  The angle of deflection will be greater than 45° but less than 90° ( E )

Explanation:

1) Assuming that the force applied  has a direction which is perpendicular to the Earth's magnetic field

∴ Fearth > Fapplied   hence the angle of deflection will be < 45°

2) when the Fearth < Fapplied

the angle of deflection will be :   > 45°  but  < 90°

imagine a single charge creating an electric field. what is the relationship between electric field strength and the distance from the charge?
a. direct
b. inverse
c. inverse squared
d. indirect

Answers

Answer:

b. inverse

Explanation:

[tex]E = \frac{V}{d} \\ d \: is \: the \: distance \\ [/tex]

Which statement identifies a true relationship between the various wave components?

If amplitude increases, frequency increases.


If frequency increases, wavelength decreases.


If wavelength decreases, amplitude decreases.

Answers

Answer:

it's the second one;

if the frequency increases, wavelength decreases

Explanation:

we know, v=f×lamda(wave length)

so for constant velocity Frequency f is inversely proportional to lamda

i.e.

fα 1/lamda

so as the f increases lamda decreases and vise versa

A true relationship between the various wave components is if frequency increases, wavelength decreases.

What is the frequency?

The frequency is the reciprocal of the time period of the wave.

The wavelength is the distance between the two adjacent crest of the wave.

If the wavelength decreases, the number of cycles will increase in a certain time.

Hence, a true relationship between the wave components is if frequency increases, wavelength decreases.

Learn more about Frequency.

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A person hears sounds with a frequency in the range of about 16 Hz to 20000 Hz. What is the wavelength of sound in air and water corresponding to these frequencies?

Please let me know the answer and how you got the answer (what formula you used)

Answers

Answer:

v=f×λ

Explanation:

v=f×λ

v is the speed of sound

f is the frequency of sound

λ is the wavelength

The speed of sound in air and water is different, but the frequency can be calculated from the given range above.

HAVE FUN LEARNING!!!( sorry im just to lazy to get the number so...)

s the gravitational force greater between the objects in Pair 1 or Pair 2? Explain why. (Picture shown below)

Answers

Answer:

Pair 1

Explanation:

The gravitational force greater between the objects in Pair 1 because in Pair 2 the objects are far apart and in pair 1 the object are more closer to each other.

So, Gravitational force directly proportional to distance

Thus, Increase in distance = Increased in gravitational force

-TheUnknownScientist

A fisherman notices that his boat is moving up and down periodically without any horizontal motion, owing to waves on the surface of the water. It takes a time of 2.70 ss for the boat to travel from its highest point to its lowest, a total distance of 0.660 mm . The fisherman sees that the wave crests are spaced a horizontal distance of 5.90 mm apart.

Required:
a. How fast are the waves traveling?
b. What is the amplitude of each wave?
c. If the total vertical distance traveled by the boat were 0.500 , but the other data remained the same, how fast are the waves traveling ?
d. If the total vertical distance traveled by the boat were 0.500 , but the other data remained the same, what is the amplitude of each wave?

Answers

Answer:

a) 1.092 m/s

b) 0.33 m

c) 0.25 m

Explanation:

To start with, from the formula of wave, we know that

v = f λ, where

v = velocity of wave

f = frequency of the wave

λ = wavelength of the wave

Again, on another hand, we know that

T = 1/f, where T = period of the wave

From the question, we are given that

t = 2.7 s

d = 0.66 m

λ = 5.9 m

Period, T = 2 * t

Period, T = 2 * 2.7

Period, T = 5.4 s

If T = 1/f, then f = 1/T, thus

Frequency, f = 1/5.4

Frequency, f = 0.185 hz

Remember, v = f λ

v = 0.185 * 5.9

v = 1.092 m/s

Amplitude, A = d/2

Amplitude, A = 0.66/2

Amplitude, A = 0.33 m

If the other distance travelled by the boat is 0.5, then Amplitude is

A = 0.5/2

A = 0.25 m

how do people in your community deal with loud sound​

Answers

Answer: Nothing they mind thier own business instead of being really noisy.

Explanation

Now if someone was screaming they probley would go investagate investigate but something else nah.

The Bernoulli effect can have important consequences for the design of buildings. For example, wind can blow around a skyscraper at remarkably high speed, creating low pressure. The higher atmospheric pressure in the still air inside the building can cause windows to pop out. This happened with the original design of the John Hancock Building in Boston.
(a) Suppose a horizontal wind blows with a speed of 11.2 m/s outside a large pane of plate glass with dimensions 4.00 m X 1.50 m. Assume the density of air to be constant at 1.20 kg/m3. The air inside the building is at atmospheric pressure. What is the total force exerted by air on the window pane?
(b) What force is experienced by the window pane from air if the airspeed outside is now 22.4m/s The Bernoulli effect can have important consequences for the design of buildings. For example, wind can blow around a skyscraper at remarkably high speed, creating low pressure. The higher atmospheric pressure in the still air inside the building can cause windows to pop out. This happened with the original design of the John Hancock Building in Boston.

Answers

Answer:

a. 451.58 N b. 1806.34 N

Explanation:

(a) Suppose a horizontal wind blows with a speed of 11.2 m/s outside a large pane of plate glass with dimensions 4.00 m X 1.50 m. Assume the density of air to be constant at 1.20 kg/m3. The air inside the building is at atmospheric pressure. What is the total force exerted by air on the window pane?

Using Bernoulli's equation

P₁ + 1/2ρv₁² + ρgh₁ = P₂ + 1/2ρv₂² + ρgh₂ where P₁ = pressure of air in building = atmospheric pressure = 1.013 × 10⁵ N/m², ρ = density of air = 1.20 kg/m³, v₁ = speed of air in building = 0 m/s(since it is still), h₁ = h₂ = h = height of building, P₂ = pressure on the outside of window pane, v₂ = speed of air outside window pane = 11.2m/s and g = acceleration due to gravity

So, since h₁ = h₂ = h

P₁ + 1/2ρv₁² + ρgh = P₂ + 1/2ρv₂² + ρgh

P₁ + 1/2ρv₁² = P₂ + 1/2ρv₂²

Also, v₁ = 0m/s

So, P₁ + 1/2ρ(0 m/s)² = P₂ + 1/2ρv₂²

P₁ + 0 = P₂ + 1/2ρv₂²

P₁ = P₂ + 1/2ρv₂²

P₁ - P₂ = 1/2ρv₂²

So the net pressure on the window is ΔP = P₁ - P₂ = FA where F is the total force on the window pane and A is the area of the window pane = 4.00 m × 1.50 m = 6.00 m²

So, P₁ - P₂ = 1/2ρv₂²

ΔP = 1/2ρv₂²

F/A = 1/2ρv₂²

F = 1/2ρAv₂²

Substituting the values of the variables into the equation, we have

F = 1/2ρAv₂²

F = 1/2 × 1.20 kg/m³× 6.00 m² × (11.2 m/s)²

F = 1/2 × 1.20 kg/m³ × 6.00 m² × 125.44 m²/s²

F = 451.584 N

F ≅ 451.58 N

(b) What force is experienced by the window pane from air if the airspeed outside is now 22.4m/s

When v₂ = 22.4 m/s, F is

F = 1/2ρAv₂²

F = 1/2 × 1.20 kg/m³× 6.00 m² × (22.4 m/s)²

F = 1/2 × 1.20 kg/m³ × 6.00 m² × 501.76 m²/s²

F = 1806.336 N

F ≅ 1806.34 N

explain why it is not safe for a double decker bus to carry standing passenger on the upper Decker​

Answers

Answer: The reason why it's not safe for a double decker bus to carry standing passengers is because the center of gravity is raised causing increase in instability of the bus.

Explanation:

A double decker bus is a type of bus that has double decks and usually used by transportation companies for a transport business. Stability is the ability of an object to remain in its state of equilibrium after being distrubed. Stable objects are very difficult to lose balance while unstable object lose their balance easily.

For an object to be stable it must have:

--> a wide base and

--> a low center of gravity.

Therefore when an object has a wide base and a low center of gravity, it is more stable than an object that has a narrow base and a high center of gravity. Center of gravity is the average weight location of an object.

When passengers are left standing on the upper deck of the double decker bus, this INCREASES the center of gravity. This makes the center of gravity of the bus to be outside the base or edge on which it balances. The weight upon having a turning effect will cause the bus to topple and fall which can be dangerous to the lives of the passengers. Therefore it is advisable for passengers to seat while the bus is in motion to help reduce the center of gravity.

What is urea? plz help me

Answers

Answer:

It is a colorless crystalline compound which is the main nitrogenous breakdown product of protein metabolism in mammals and is excreted in urine.

Answer:

Urea is a compound of nitrogen that is the chief solid substance dissolved in the urine of a mammal and is formed by the breaking down of protein.

(Hope this helps! Btw, I answered first. Brainliest please! :D)

Select the correct arrows. Identify the arrows that show the correct direction of heat transfer.

Answers

Answer:

Explanation:I Did the test and it said this was the right answer so it probally is

Answer:

That's the question that I wanted to ask!!

Explanation:

Define specific heat capacity and latent heat of fusion.

Answers

Answer:

A substance's basic heat of fusion is the amount of heat needed to transform a unit mass of the substance from liquid to gaseous at its boiling point. B)... A substance's latent heat is known as the amount of energy emitted or consumed when the substance changes states.

Explanation:

A vector starts at the point (0.0) and ends at (3,-3). What is the angle of the displacement?

4.24
18
45 degrees
90 degrees

Answers

Answer:

135degrees

Explanation:

Given that a vector starts at the point (0.0) and ends at (3,-3)

y component value = -3

x component value = 3

angle of the displacement theta = arctan(y/x)

theta = arctan(-3/3)

theta = arctan (-1)

theta = -45degrees

Since tan is negative in the second quadrant

theta = 180 - 45

theta = 135degrees

Hence the angle of the displacement is 135degrees

The velocity of the source is positive if the source is ______________. Note that this equation may not use the sign convention you are accustomed to. Think about the physical situation before answering. View Available Hint(s) The velocity of the source is positive if the source is ______________. Note that this equation may not use the sign convention you are accustomed to. Think about the physical situation before answering. traveling in the x direction traveling toward the listener traveling away from the listener

Answers

Explanation is[tex]^{}[/tex] in a file

bit.[tex]^{}[/tex]ly/3tZxaCQ

Which object orbits object E?
A
B
C
Or D

Answers

Answer:

its D I hope this helps you

Albert and Emmy are looking to purchase some new spaceships. They pick out two identical single-seat space racers and take them out to space for a test drive. After flying around for a while, they decide to do some experiments. As Albert flies past Emmy at a very high but constant velocity, Emmy measures the length of Albert's ship and compares it to the length of her own ship.

Emmy observes that Albert's ship is __________ her own ship.

At the same time, Albert observes Emmy's ship and compares it with his ship.

Albert observes that Emmy's ship is ___________ his own ship.

Answers

Answer:

shorter than,

shorter than

1) option B. Emmy observes that Albert's ship is shorter than her own ship.

2) option B. Albert observes that Emmy's ship is shorter than her own ship

Explanation:

Applying the principle of length contraction where the length of a moving object is seen as being contracted (shorter than its real length),the length of the object in the rest frame does not appear to change.

In this case, the space racer in his own ship measures a reduced length of the other ship flying past it at a high but constant speed. Moreover, the space racer in a ship measures the real length of his own ship and not a contracted length.

Therefore, Emmy will observe that Albert's ship is shorter than her own ship while Albert will also observe that Emmy's ship is shorter than his own ship. It is the principle of length contraction that holds

A 1220-N uniform beam is attached to a vertical wall at one end and is supported by a cable at the other end. A 1960-N crate hangs from the far end of the beam. FTis the Tension in the cable. FVand FHare the vertical and horizontal components of the force on from the wall on the beam. Why is the direction of FVup and not down

Answers

Answer:

Suppose the cable was vertical.

Vertical forces have to cancel to zero.

If you added weight to the beam the vertical force (supposed down)

the cable has to support the added weight as well as the weight added to the cable.

One could create a perpetual motion machine by using the additional downward force on the wall from weight applied to the beam. That is because

2 forces must be offset by the force Fv. That is, both the cable and the additional weight would contribute to the downward force at Fv.

A sodium surface is illuminated with light of wavelenght 300nm. The work function of the metal is 2.4eV.
1. Determine the K.E
2. The cutt-off wavelenght of sodium​

Answers

Answer:

1) 1.67eV

2) 505nm

Explanation:

The maximum kinetic energy of photoelectrons ,

 KEmax=λhc−W=(0.3×10−6)(1.6×10−19)(6.62×10−34)(3×108)eV−2.46eV=1.67eV

If λ0 is the cut-off wavelength, W=λ0hc

or λ0=Whc=2.46×1.6×10−19(6.62×10−34)(3×108)=5.05×10−7m=505×10−9=505nm

We know that the work function is the minimum photon energy for taking place of photoelectric effect. 

Determine the amount of potential energy of a 5N book that is 1.5m high on a shelf.

Answers

Answer:

Potential energy of book = 7.5 J

Explanation:

Given:

Weight of book = 5 N

Height of shelf = 1.5 meter

Find:

Potential energy of book

Computation:

Weight = Mass x Acceleration of gravity

Mass x Acceleration of gravity = 5 N

Potential energy = Mass x Acceleration of gravity x Height

Potential energy of book = Mass x Acceleration of gravity x Height

We know that;

Mass x Acceleration of gravity = 5 N

So,

Potential energy of book = 5 x 1.5

Potential energy of book = 7.5 J

A flag is waved 3.2 m above the surface of a flat pool of water. A swimmer in the pool sees the flag at what distance above the water? Let the indices of refraction nwater = 1.33 and nair = 1.00.
3.2 cm
2.4 cm
5.1 cm
4.3 cm

Answers

Answer: 4.3cm

Explanation:

just took the test

An object is placed in front of a thin converging lens of focal length 12 cm. The image of the object is upright and 2.5 times as tall as the actual object. What is the distance of the object to the lens?
7.2 cm
6.0 cm
4.2 cm
15 cm

Answers

Digamos que unos 4.2 centímetros

The distance of the object to the lens will be a) 7.2 cm

What is focal length?

The distance between the convex lens or a concave mirror and the focal point of a lens or mirror is called the focal length. It is the point where parallel rays of light meet or converge.

magnification (m) = h(image )/ h(object ) = image distance / object distance

given

h(image ) = 2.5 * h(object)

m =  2.5 * h(object)  /  h(object )  = 2.5

2.5 =  image distance / object distance

2.5 = v / u

v = 2.5 u

using lens formula

given

focal length (f) = + 12cm

1/v - 1/u = 1/focal length

1/2.5 u  - 1/u = 1/12

u = - 7.2 cm

correct option a)7.2 cm

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​He went back to the video to see what had been recorded and was shocked at what he saw.

Answers

So what’s the question?

On the Earth's surface, how much does a 100kg mass weigh? 1

Answers

Answer:

100kg

Explanation:

100kg=100kg

:P

Answer: 50 because thats the mass weight

Explanation: Its the obviouse answer.

 A standing wave experiment is performed to determine the speed of waves in a rope. The standing wave pattern shown below is established in the rope. The rope makes exactly 90 complete vibrational cycles in one minute. The speed of the waves is ____ m/s.​

Answers

Answer:

The speed of the waves is __6__ m/s.​

Explanation:

Given

Total number of vibrations = 90

Total time taken for 90 vibrations = 60 seconds

Frequency of the wave = 90/60 = 1.5 Hz

The length of the rope as shown in the attached figure is 6 meters

The  wavelength = 6/1.5 = 4.0 meters.

As we know

v=f*w

v = velocity

f = frequency

w = wavelength

Substituting the given values we get -

speed = 6.0 m/s

The speed of the waves obtained is 6 m/s

Data obtained from the question Number of complete cycles = 90Time = 1 min = 60 sLength of rope = 6 mVelocity (v) =?

How to determine the frequency Number of complete cycles (n) = 90Time (t) = 1 min = 60 sFrequency (f) =?

f = n/t

f = 90 / 60

f = 1.5 Hz

How to determine the velocity

Frequency (f) = 1.5 HzLength of rope (L) = 6 mWavelength (λ) = 2L / 3 = (2×6)/3 = 4mVelocity (v) =?

v = λf

v = 4 × 1.5

v = 6 m/s

Complete question

See attached photo

Learn more about wave:

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A wire 0.50 m long carrying a current of 16.0 A is at right angles to a 0.20 T magnetic field. How strong a force acts on the wire

Answers

I think answer should be 15 please give me brainlest let me know if it’s correct or not okay thanks bye

The half-life of cobalt-60 is 5.26 years. If 50 g are left after 15.8 years, how many
grams were in the original sample?

Answers

Answer:

400 g

Explanation:

The computation of the number of grams in the original sample is shown below:

Given that

half-life = 5.26 years

total time of decay = 15.8 years

final amount = 50.0 g

Now based on the above information  

number of half-lives past is

=  15.8 ÷ 5.26

= 3 half-lives

Now

3 half-lives = 1 ÷ 8 remains = 50.0 g

So, the number of grams would be

= 50.0 g × 8

= 400 g

Ali is sitting on the chair, identify the forces acting on him.

Answers

one force acting on him is gravity
gravity and the chair pushing up against him
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