What is true about the completely simplified sum of the polynomials 3x2y²-2xy and -3x²y² + 3xy?

The picture are the answer choices and i only have 20 mins left so please help!​

Answer:

0.2÷3.0=15.0

Step-by-step explanation:

Answer:

57

Step-by-step explanation:

Answer:

Step-by-step explanation:

The inequality equation will be 0 < -15 - y. Then the value of the variable y is less than negative 15.

Inequality is defined as an equation that does not contain an equal sign. Inequality is a term that describes a statement's relative size and can be used to compare these two claims.

Zero is less than negative fifteen decreased by y, can be written as mathematically

0 < -15 - y

Then solving for y, we have

y < -15

The value of the variable y is less than negative 15.

More about the inequality link is given below.

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Answer:

B

Step-by-step explanation:

using the identity

sin²x + cos²x = 1 ( subtract 1 from both sides )

sin²x + cos²x - 1 = 0 ( subtract sin²x from both sides )

cos²x - 1 = - sin²x

then

[tex]\frac{cos^20-1}{4sin^20}[/tex]

= [tex]\frac{-sin^20}{4sin^20}[/tex] ← cancel sin²Θ on numerator and denominator

= [tex]\frac{-1}{4}[/tex]

= - [tex]\frac{1}{4}[/tex]

Answer: 1190 pages

Step-by-step explanation:

The word problem states that Grace has a set of 14 notebooks, and each notebook has 85 pages. To find the total number of pages, we want to multiply the number of pages in each book by how many books there are.  

14×85=1190 pages

To find the area of a complex shape:

 ⇒ must cut the whole shape into a simpler shape

Let's calculate:

             [tex]Area = \frac{1}{2}*4*8 + \frac{1}{2}*4*8=16+16=32\\[/tex]

             [tex]Area = \frac{1}{2}*4*10 + \frac{1}{2}*4*10=20+20=40[/tex]

             [tex]Area = 4 * 4=16[/tex]

Total Area: 32 + 40 + 16 = 88 in²

Answer: 88 in²

Hope that helps!

Answer:

slope has a gradient of -3/5

Step-by-step explanation:

change in y / change in X

-6 / 10

for the length use Pythagoras

Answer:

FA: Chord

BO: Radius

CO: Radius

DO: Radius

EO: Radius

CE: Diameter

Step-by-step explanation:

Hello!

Some lines in a circle:

Segment FA

This has endpoints inside the circle, but doesn't go through the center. This is a chord.

Segment BO

BO has an endpoint on the center and and an endpoint on the perimeter. This is a radius.

Segment CO

This is also a radius, it has an endpoint on the center and another endpoint on its perimeter.

Segment DO

This is a radius, it has n endpoint on the center and another endpoint on the perimeter

Segment EO

Another radius, with a an endpoint on the center and another endpoint on the perimeter.

Segment CE

A diameter. It has two endpoints on the perimeter of the circle and goes through the center of the circle.

Answer:

3

The degree of a polynomial is the highest power of any variable in the polynomial equation.

Here the highest power is 3 of the monomial with co-efficient of 2.

The student is incorrect, the actual x-intercept is (5, 0).

Here we have the equation:

x + 2y = 5

The student says that the x-intercept is the point (0, 5).

So if you look at the point you already can see that the student is incorrect, this is because the x-intercept always must have a y-value of 0. (the graph only intercepts the x-axis when y = 0).

So the point (0, 5) can't be an x-intercept.

For the given function:

x +2y = 5

The x-intercept is given by:

x + 2*0 = 5

x = 5

So it is (5 , 0).

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Answer:

Answer E is correct

Step-by-step explanation:

We know that,

[tex](x^ay^b)^c=x^a^cy^b^c[/tex]

Let us use the above to find the answer to this question.

Let us solve it now.

[tex](a^\frac{2}3} b^\frac{1}{3})^\frac{1}{2}[/tex]

[tex]a^\frac{2}3}^*^ \frac{1}{2} *b^\frac{1}{3}^*^\frac{1}{2}[/tex]

[tex]a^\frac{2*1}{3*2} * b^\frac{1*1}{3*2}[/tex]

[tex]a^\frac{2}{6} * b^\frac{1}{6}[/tex]

Here, we can simplify the [tex]a^\frac{2}{6}[/tex] as [tex]a^\frac{1}{3}[/tex] by dividing the numerator and denominator by 2.

Therefore, the answer will be,

[tex]a^\frac{1}{3} b^\frac{1}{6}[/tex]

Types of Triangles (Angles):

---Acute = all angles are less than 90 degrees

---Right = one angle is equal to 90 degrees

---Obtuse = one angle is greater than 90 degrees

Types of Triangles (Side Lengths):

---Equilateral = all sides are the same length

---Isosceles = two sides are the same length

---Scalene = all sides are different lengths

The following triangle is obtuse and scalene. It has one angle that is greater than 90 degrees and its sides are all different lengths.

Hope this helps!

B. Scalene

E. Obtuse

Triangles can be classified in 2 different ways. They can be classified based on their sides and angles.

Sides

There are 3 different categories for the sides: scalene, isosceles, and equilateral.

Angles

Triangles can be classified as acute, obtuse, or right based on their angles.

Scalene Obtuse Triangle

The triangle above has no equal sides, so it must be scalene. Additionally, because one of the angles is 132 degrees, it must be an obtuse triangle.

Answer:

10.19

Step-by-step explanation:

Use the Pythagorean Theorem:

[tex]a^{2}+b^{2}=c^{2}[/tex]

Substitute the numbers given:

[tex]11^{2}+b^{2}=15^{2}[/tex]

[tex]121+b^{2}=225\\ b^{2}=225-121\\ b^{2}=104\\ \sqrt b^{2}= \sqrt{104} \\ b=10.19[/tex]

Answer:

  TRUE: A, B, C

  False: D

Step-by-step explanation:

A full circle of 360° has a radian measure of 2π radians. The relationship is proportional, so π radians is 180°.

__

A. An angle that measures π/4 radians also measures 45°. TRUE

  45° × π/180° radians = π/4 radians

B. An angle that measures 180° also measures π radians. TRUE

  180° × π/180° radians = π radians

C. An angle that measures 60° also measures π/3 radians. TRUE

  60° × π/180° radians = π/3 radians

D. An angle that measures π/3 radians also measures 30°.​ FALSE

  30° × π/180° radians = π/6 radians

Answer:

ok so

Step-by-step explanation:

add them alll up which is 33. then do 33 divided by 10 because thats how many numbers there are and mean is adding all the numbers up and dividing them so 3.3  degrees celsius

Answer:

Given a bus can ferry a maximum of 12 people .by setting up an inquality find minimum number of bus that are needed to ferry 80 people

Given a bus can carry a maximum of 12 people. We need to find minimum number of buses to carry 80 people.

Now 12 people can go in 1 bus.

Therefore 1 person can go in 1/12 bus

Now 1 person can go in 1/12 bus

Therefore 80 people can travel in 1/12 x 80

                                                   = 6.6  

                                                    = 7

Therefore minimum buses needed will be 7

Now we can write inequality as 12 x x > = 80

                    Or x ≥ 80 / 12

       or x > = 6.6

Step-by-step explanation:  Hopes it help

                                            Please mark my answer as a brainliest!

Answer:

16 red marbles

Step-by-step explanation:

8 red

9 yellow

7 green

total = 8 + 9 + 7

p(red) = 8/24 = 1/3

Add r number of red marbles to the total.

8 + r red

9 yellow

7 green

total = 8 + r + 9 + 7 = r + 24

p(red) = (8 + r)/(r + 24) = 3/5

Cross multiply.

40 + 5r = 72 + 3r

2r = 32

r = 16

Answer: 16 red marbles

Answer:

16

Step-by-step explanation:

bag red: 8 + x

yellow:9

green 7/24

3/5 = 8+ x/24+ x

5(8 + x) = 3 (24 + x)

40 + 5x

-40 -3x = 72 + 3x

-40 -3x    -40 - 30

2x/2 = 32/2  so,x = 16

[tex]\huge\underline{Answer -}[/tex]

[tex] \huge{\implies \: \frac{ - 2 \frac{1}{4} }{ - \frac{ 2}{3} }} \\ \\ \\ \\ \huge{\implies \: \frac{ \frac{ - 9}{4} }{ \frac{ - 2}{3} } } \\ \\ \\ \\ \huge{\implies \: - \frac{9}{4} \div (\frac{ - 2}{3} )}[/tex]

therefore , option ( 2 ) is correct.

hope helpful -,-

Answer:

2, 10, 50, 250

Step-by-step explanation:

For geometric sequences, multiply the previous term by the common ratio.

Using the formula for geometric sequences [tex]a_{n} =ar^{n-1}[/tex] , with [tex]a_{n}[/tex] being the nth term (so n=4 for the fourth term), a being the first term, and r being the common ratio.

Our starting term is 2. So that is automatically the first term of the four.

Second term:

[tex]a_{2} =2*5^{2-1}=2*5^1=2*5=10[/tex]

Third term:

[tex]a_{3} =2*5^{3-1}=2*5^2=2*25=50[/tex]

Fourth term:

[tex]a_{4} =2*5^{4-1}=2*5^3=2*5*5*5=10*25=250[/tex]

The total surface area of the given pyramid is:

A = 39ft²

The total surface area will be equal to the sum of the areas of the square and the 4 triangles.

Remember that for a square of side length S, the area is:

A = S².

In this case, S = 3ft, then:

A = (3ft)² = 9ft².

Now, the area of a triangle of base B and height H is:

A = B*H/2.

Here we can see that the triangles have a base of 3ft (the sides of the square) and a height of 5ft, then the area of each triangle is:

A = (3ft)*(5ft)/2 = 7.5 ft²

Then the total area of the figure is:

A = 4*(7.5 ft²) + 9ft² = 39ft²

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The positive measure is 220° and the negative measure is -140°.

First, we know that the reference angle is 40°, and it lies on the third quadrant.

So these 40° are measured from the negative x-axis (the axis where the quadrant starts).

This means that the angle measured in the standard way (from the positive x-axis) measures:

M = 40° + 90° + 90° = 220°.

To find the negative measure, we remember that any angle A is equivalent to:

B = A + n*360°.

Where n is an integer.

If we take n = -1 for our angle, we get:

M' = 220° + (-1)*360° = -140°.

So the positive measure is 220° and the negative measure is -140°.

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Answer:

Point A:

(1, 1) -----> (-1, 1)

Step-by-step explanation:

When reflecting over the y-axis, take the opposite of the x-coordinate. That means if the coordinate is positive then it becomes negative, and if it is negative then it becomes positive.

(x, y) -------> (-x, y)

Point A:

(1, 1) -----> (-1, 1)

Answer:

  (a, y) = (10, 25)

Step-by-step explanation:

The two constraints give rise to two inequalities: one for the maximum number of pieces shipped, and one for the minimum revenue. A solution is a point on the graph where the inequality solutions overlap.

__

  We're told to use 'a' for the number of chairs, and 'y' for the number of tables.

  a +y ≤ 45 . . . . . . the maximum number that can be shipped is 45

  200a +650y ≥ 16000 . . . . . revenue must be at least 16000

The line for the revenue equation has a slope of -200/650 = -4/13. The solution space is above this line.

The line for the quantity shipped equation has a slope of -1, somewhat steeper. The solution space is below this line.

The boundary lines combine to define a wedge-shaped solution area in the left part of the first quadrant. One point that can be found in that area is ...

  (a, y) = (10, 25)

One possible solution is to sell 10 chairs and 25 tables.