What would the answer be?

Answer:

Ba²⁺(aq) + SO₄²⁻(aq) ⇒ BaSO₄(s)

Explanation:

Let's consider the molecular equation for the reaction between Ba(NO₃)₂ and Na₂SO₄. This is a double displacement reaction in which BaSO₄ forms a white precipitate.

Ba(NO₃)₂(aq) + Na₂SO₄(aq) ⇒ BaSO₄(s) + 2 NaNO₃(aq)

The complete ionic equation includes all the ions and insoluble species.

Ba²⁺(aq) + 2 NO₃⁻(aq) + 2 Na⁺(aq) + SO₄²⁻(aq) ⇒ BaSO₄(s) + 2 Na⁺(aq) + 2 NO₃⁻(aq)

The net ionic equation includes only the ions that participate in the reaction and insoluble species.

Ba²⁺(aq) + SO₄²⁻(aq) ⇒ BaSO₄(s)

Answer:

Sodium (Na)

Helium

Magnesium (Mg).

Explanation:

From the periodic table, we will understand that the group 1 metals are the alkali metal. However, the period runs from left to right on the periodic table while the group runs from up to down in the periodic table. In period 3, the alkali metal present there with one valence electron in its outermost shell is sodium (Na).

The only noble gas exists in the last group, group zero of the periodic table. However, the only noble gas with two electrons in its outermost shell is called Helium

The ALkaline earth metals are group 2 metals. They are usually shiny metals and the ability to lose 2 electrons in their outermost electron shell. The alkaline earth metal located in period 3 is Magnesium (Mg).

Lots of fonts, you can also insert those images with the checkered background (they show up clear) and decorate it, also make sure that you have proper spacing a paragraph structure

Answer:

C) Organic Weathering

Explanation:

Heat and Cold

And if some people start reporting and making fun of me in this answer don't listen to them.

They are hunting me down.

Answer:

The proton gradient produced by proton pumping during the electron transport chain is used to synthesize ATP. Protons flow down their concentration gradient into the matrix through the membrane protein ATP synthase, causing it to spin (like a water wheel) and catalyze conversion of ADP to ATP.

Answer:

c is correct option

according to the question.

Scientists classify organisms into three domains and six kingdoms. In Fungi kingdom are yeasts classified because they are heterotrophic. Therefore, option C is correct.

An organism is referred to be a heterotroph if it is unable to manufacture food on its own and must obtain it from other sources of organic carbon, primarily plant or animal materials.

All fungi are heterotrophic, which means they draw their energy from other living things.

Since they share some traits with fungi, such as the presence of chitin in their cell walls, extracellular digestion, saprophytic feeding, asexual reproduction by budding, and the ability to store food as glycogen, yeast cells are categorised as fungi.

Thus, option C is correct.

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The statement which is  given below describe a homogeneous catalyst.

"It is in the same phase as the reactants"

The catalyst which have similar phase to the reactant of the reaction is called homogeneous catalyst.

Mostly in  homogeneous catalyst, catalyst present in liquid form.

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Answer:

15.2 g H2

Explanation:

2H2O -> 2H2 + O2

9.06 x 10^24 molecules x (1 mol/6.022 x 10^23 molecules) x (2 mol H2/2 mol H2O) x (1.008 g/1 mol) = 15.2 g H2

Answer:

C

Explanation:

thermal energy is the another name for heat

Answer:

The balance reaction is

2Pb(NO3)2 ----》4NO2+2PbO+O2

hence the value of a,b,c,d are 2,4,2,1 respectively!

Answer:

calcium has more mass

Explanation:

1 mole calcium mass= 40.078 g

1 mole magnesium mass= 24.305 g

Answer:

161.54 g of N₂

Explanation:

The balanced equation for the reaction is given below:

2NaN₃ —> 2Na + 3N₂

Next, we shall determine the mass of NaN₃ that decomposed and the mass of N₂ produced from the balanced equation. This is illustrated below:

Molar mass of NaN₃ = 23 + (3×14)

= 23 + 42 = 65 g/mol

Mass of NaN₃ from the balanced equation = 2 × 65 = 130 g

Molar mass of N₂ = 2 × 14 = 28 g/mol

Mass of N₂ from the balanced equation = 3 × 28 = 84 g

SUMMARY:

From the balanced equation above,

130 g of NaN₃ decomposed to produce 84 g of N₂.

Finally, we shall determine the mass of N₂ produced by the decomposition of 250 g of NaN₃. This can be obtained as follow:

From the balanced equation above,

130 g of NaN₃ decomposed to produce 84 g of N₂.

Therefore, 250 g of NaN₃ will decompose to produce

= (250 × 84)/130 = 161.54 g of N₂

Thus, 161.54 g of N₂ were obtained from the reaction.

Answer:

2

Explanation:

WO2(s) + 2H2(g) -> W(s) + 2H2O(l)

Answer:

when the substance is decrease

Explanation:

Answer:

Explanation:

From the given information:

The concentration of metal ions are:

[tex][Ca^{2+}]= \dfrac{0.003474 \ M \times 20.49 \ mL}{10.0 \ mL}[/tex]

[tex][Ca^{2+}]=0.007118 \ M[/tex]

[tex][Mg^2+] = \dfrac{0.003474 \ M\times (26.23 - 20.49 )mL}{10.0 \ mL}[/tex]

[tex]=0.001994 \ M[/tex]

Mass of Ca²⁺ in 2.00 L urine sample is:

[tex]= 2.00 L \times 0.001994 \dfrac{mol}{L} \times \dfrac{40.08 \ g}{1 \ mol}[/tex]

= 0.1598 g

Mass of Ca²⁺ = 159.0 mg

Mass of Mg²⁺ in 2.00 L urine sample is:

[tex]= 2.00 L \times 0.007118 \dfrac{mol}{L} \times \dfrac{24.31 \ g}{1 \ mol}[/tex]

= 0.3461 g

Mass of Mg²⁺ = 346.1 mg

Answer:

a) 210.3 g/mol

b) 210.2 g/mol

c) 384.5 g/mol

Explanation:

First step we will calculate the molar masses of ; carbon atom, hydrogen atom and  oxygen atom in each .

Molar mass of dibenzyl ketone

Molar mass of dibenzyl ketone = ∑ molar masses of atoms in dibenzyl ketone

= carbon( 15 ) = 15 ( 12.0107 ) + oxygen ( 14 ) = 1 ( 15.999 ) + hydrogen(14) =14(1.00784)

= 210.26926 ≈ 210.3 g/mol

 Molar mass of benzil

Molar mass of Benzil =  ∑ molar masses of atoms in  Benzil

= carbon( 14) = 14(12.0107) + oxygen(2) = 2 ( 15.999) +  hydrogen(10) =10(1.00784)

= 210.2262 ≈ 210.2 g/mol

Molar mass of 2,3,4,5-tetraphenylcyclopentadienone

Molar mass  = ∑ molar masses of atoms

= carbon ( 29) = 29(12.0107) + oxygen (1) = 1( 15.999 ) + hydrogen(20) = 20(1.00784 )

≈ 384.5 g/mol

Answer:

False, it becomes colourless in acidic solutions and turns pink in basic solutions

Answer: C

Explanation:

he never had evidence in the first place that was nearly enough.

Answer:

Its Kinetic  energy

Explanation:

You are giving the bow potential energy. "When you let the bow go, it returns to its original shape. The energy is transformed to kinetic energy and transferred to the arrow"

Answer:

potential

Explanation:

the energy is potential lol

Answer:

may you include the table and actual question? would love to help but I need clarity on what is being asked.

Explanation:

Answer:

98.6g is the mass of the heptahydrate

Explanation:

The hydrated magnesium sulfate contains 7 moles of water per mole of magnesium sulfate. 1 mole of MgSO₄ dehydrated is 1 mole of MgSO₄.7H₂O

To solve this question we must find the moles of MgSO₄. These moles = Moles of MgSO₄.7H₂O. Then, we must convert the moles to mass:

Moles MgSO₄ -Molar mass: 120.366g/mol-:

48g * (1mol / 120.366g) = 0.40 moles MgSO₄ = moles MgSO₄.7H₂O

Mass MgSO₄.7H₂O -Molar  mass: 246.47456 g/mol-:

0.40 moles MgSO₄.7H₂O * (246.47456 g / 1mol) =

98.6g is the mass of the heptahydrate

Answer: [tex]K_{sp}=1.25\times 10^{-14}[/tex]

[tex]pK_{sp}=13.90[/tex]

Explanation:

Solubility product is defined as the equilibrium constant in which a solid ionic compound is dissolved to produce its ions in solution. It is represented as [tex]K_{sp}[/tex]  

The equation for the ionization of magnesium phosphate is given as:

[tex]Mg_3(PO_4)_2\rightarrow 3Mg^{2+}+2PO_4^{3-}[/tex]

 When the solubility of [tex]Mg_3(PO_4)_2[/tex] is S moles/liter, then the solubility of [tex]Mg^{2+}[/tex] will be 3S moles\liter and solubility of [tex]PO_4^{3-}[/tex] will be 2S moles/liter.

Thus S = 0.173 g/L or [tex]\frac{0.173g/L}{262.8g/mol}=0.00065mol/L[/tex]

[tex]K_{sp}=(3S)^3\times (2S)^2[/tex]

[tex]K_{sp}=108S^5[/tex]

[tex]K_{sp}=108\times (0.00065)^5=1.25\times 10^{-14}[/tex]

[tex]pK_{sp}=-log(K_{sp})=\log (1.25\times 10^{-14})=13.90[/tex]

The value of Ksp and pKsp for the given reaction is 1.25 × 10⁻¹⁴ and 13.90 respectively.

Solubility product constant (Ksp) is define as the product of the solubilities of the products, present in any chemical reaction.

Given chemical reaction will be represented as:

Mg₃(PO₄)₂ → 3Mg²⁺ + 2PO₄³⁻

Solubility of Mg₃(PO₄)₂ = 0.173 g/L or 0.173g/L / 262.8g/mole = 0.00065mol/L
Now for the given reaction let we consider that solubility of Mg₃(PO₄)₂ be x, solubility of Mg²⁺ be 3x and solubility of PO₄³⁻ will be 2x and equation for Ksp will be written as:
Ksp = [Mg²⁺]³[PO₄³⁻]²

Ksp = [3x]³[2x]²

Ksp = 108[x]⁵

Now we pot the solubility value of x as the solubility of Mg₃(PO₄)₂ & we get,

Ksp = 108(0.00065)⁵

Ksp = 1.25 × 10⁻¹⁴

Now we calculate the value of pKsp as:
pKsp = -log(Ksp)

pKsp = -log(1.25 × 10⁻¹⁴)

pKsp = -(-13.90) = 13.90

Hence value of pKsp is 13.90.

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Answer:

533.2 torr.

Explanation:

The following data were obtained from the question:

Mole of N₂ = 1.45 moles

Moles the He = 0.659 mole

Total pressure = 775 torr

Partial pressure of N₂ =?

Next, we shall determine the mole fraction of N₂. This can be obtained as follow:

Mole of N₂ = 1.45 moles

Moles the He = 0.659 mole

Total mole = 1.45 + 0.659 = 2.109 moles

Mole fraction of N₂ = Mole of N₂ / total mole

Mole fraction of N₂ = 1.45 / 2.109

Mole fraction of N₂ = 0.688

Gina, we shall determine the partial pressure of N₂. This can be obtained as follow:

Total pressure = 775 torr

Mole fraction of N₂ = 0.688

Partial pressure of N₂ =?

Partial pressure of N₂ = total pressure × mole fraction of N₂

Partial pressure of N₂ = 775 × 0.688

Partial pressure of N₂ = 533.2 torr.

Therefore, the partial pressure of N₂ is 533.2 torr.

6.45 mole of fluorine are  required to completely react with 2.15 mole of sulfur according to the stoichiometry of the reaction .

It is the determination of proportions of elements or compounds in a chemical reaction. The related relations are based on law of conservation of mass and law of combining weights and volumes.

Stoichiometry is used in quantitative analysis for measuring concentrations of substances present in the sample.

In the given example the balanced chemical reaction is as follows:

S +3 F₂ [tex]\rightarrow[/tex] SF₆

According to the reaction, 1 mole of sulfur reacts with 3 moles of fluorine to yield 1 mole of sulfur hexafluoride.

∴2.15 mole of sulfur requires 2.15×3=6.45 mole of fluorine.

Hence, 6.45 mole of fluorine are required to completely react with 2.15 mole of sulfur.

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Answer:

B. equal numbers of molecules

Explanation:

Answer:

The answer is C if its wrong you can report my answer I'm 100% sure its C

Answer:

B 1650

Explanation:

Answer:

There are 0.379 moles of Ca in the given sample.

Explanation:

Hey there!

We're given that we have 15.2 grams of Ca (Calcium). We need to convert grams to moles.

There are many different conversion types for moles. A few examples are:

There are really endless possibilities for conversion factors. Since we want to find the number of moles in a certain sample, we first need to define what a mole is.

A mole is one unit of a certain item. For instance, one cup would be equivalent to one mole. Moles are simply a hypothetical unit in chemistry that act as a placeholder.

Now, how do we find the number of moles?

We know that a mole of something is one of that substance. In this case, we're referring to one atom of Calcium.

Therefore, we need to reference a periodic table to understand what the mass of one atom of calcium is equivalent to. I'll be using the official AP Chemistry periodic table as issued by the College Board.

When we reference the periodic table, we see the mass of one atom of calcium is equivalent to 40.08 amu (atomic mass units).

We learn in chemistry that we can use the terms amu and grams interchangeably, so we have learned that one mole of calcium is equivalent to 40.08 grams.

How do we work this out?

Now, we need to find out how many moles are in 15.2 grams of calcium. We can use dimensional analysis to work this out.

Our starting unit will be 15.2 grams of Ca.

We want to convert this into moles, so we need to cancel out our grams value. Additionally, since we know that we have 40.08 grams of Ca in one mole, we can set these up as two ratios:

These ratios can be used to express the relationship between the moles of calcium and the mass of one calcium atom. However, we need our value of grams to cancel out, so since we will be using cross multiplication in our dimensional analysis, we need to use the ratio with grams on the bottom.

Now that we have selected our ratio, we can set up a multiplication problem of our two ratios:

[tex]\displaystyle \text{15.2 grams Ca} \times \frac{\text{1 mole Ca}}{\text{40.08 grams Ca}}[/tex]

We assume that we have a denominator of 1 below 15.2 grams Ca.

Now, we perform our multiplication.

[tex]\displaystyle \frac{\text{15.2 grams Ca} \ \times \ \text{1 mole Ca}}{\text{40.08 grams Ca}}[/tex]

We see that our remaining unit is going to be mole(s) Ca, so we can go ahead and drop our grams Ca unit.

[tex]\displaystyle \frac{\text{15.2} \ \times \ \text{1 mole Ca}}{\text{40.08}}[/tex]

Now, we need to simplify a little bit.

[tex]\displaystyle \frac{\text{15.2}}{\text{40.08}} = \text{? moles Ca}[/tex]

Finally, let's divide our fraction and evaluate our equation to find the value of moles Ca.

[tex]\displaystyle \frac{15.2}{40.08} = \text{0.379241517 moles Ca}[/tex]

Are we done yet?

Not just yet! To complete our work, we need to find the number of significant figures we can use. We are given two values in which we can use to judge how many significant figures we are limited to.

In chemistry, we always use the least number of significant figures for precision calculations, so we need to round our answer to three significant figures.

[tex]0.379241517 \approx 0.379[/tex]

Therefore, there are approximately 0.379 moles of Ca in the given sample.