Answer:
94%
Explanation:
204/216=.94444
.94444*100=94.44%
The diagram represents a beaker containing sugar,water, and sand. The sugar is dissolved in the water, creating a solution. The sand has settled to the bottom of the beaker. Describe one method to separate the sand from the other substances in the beaker.
Answer:
boiling
Explanation:
because heat dissolve sugar and not dissolve sand
One method to separate the sand from the other substances in the beaker is filtration.
What is separation?A separation process is a method for separating two or more separate product mixtures from a mixture or solution of chemical ingredients.
To put it another way, it's a scientific method for discriminating between two or more substances in order to achieve purity. On of the simple method of separating sand from the solution of water and sugar is filtration. As sand is insoluble in water so by the use of filter we can separate out sand.Hence one separation method is filtration.
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Does heat flow out of the atmosphere (HQ)
change during the day?
Answer:
The heat flow into Earth's atmosphere varies as the Sun rises and sets, gradually increasing during the day and falling to zero at night.
Explanation:
Heat radiates from the ground into the lower atmosphere. In conduction, heat moves from areas of more heat to areas of less heat by direct contact. Warmer molecules vibrate rapidly and collide with other nearby molecules, transferring their energy.
Find the molecular weight of CO
Answer:
The molecular weight of CO is 28.01g/mole.
You perform an experiment to determine the density of the penny in the lab. To do this you count out 10 pennies and measure their mass on an analytical balance. The mass of the 10 pennies was found to be 24.0416 grams. To determine the volume of the pennies you add water to a graduated cylinder and the volume is found to be 20.23 mL. After 10 pennies have been carefully added to the graduated cylinder, the volume is now found to be 23.13 mL. Calculate the density of the penny in g/mL and report your answer to the correct number of significant figures.
Answer:
8.29g/mL
Explanation:
Density (g/mL) = mass(g)/volume(mL)
According to this question, an experiment is conducted on the density of penny in the laboratory found out that the masses of the 10 pennies was found to be 24.0416g while the volume of the pennies is as follows:
Volume of water + graduated cylinder= 20.23 mL.
Volume of pennies + water = 23.13 mL.
Hence, volume of pennies is 23.13 - 20.23
= 2.9mL
Density = 24.042g ÷ 2.9mL
Density = 8.29g/mL
How many elements in a periodic table?
Which of the following best describes density?
- the relationship between length and mass
- the relationship between volume and area
- the relationship between mass and area
- the relationship between mass and volume
Answer:
the relationship between mass and volume
Molar mass of propan-1-ol
Answer:
60g/mol.
Explanation:
TO FIND :-
Molar mass of Propan-1-olFACTS TO KNOW BEFORE FINDING ANSWER :-
Chemical formula of Propan-1-ol = CH₃CH₂CH₂OH [or] C₃H₈OMolar mass of C = 12g/mol.Molar mass of H = 1g/mol.Molar mass of O = 16g/mol.SOLUTION :-
Molar mass of C₃H₈O = 3(Molar mass of C) + 8(Molar mass of H) + 1(Molar mass of O)
⇒ Molar mass of C₃H₈O = (3×12) + (8×1) + 16 = 36 + 8 + 16 = 60g/mol.
The combustion of acetylene gas is represented by this equation: 2C2H2(g) + 5O2(g) → 4CO2(g) + 2H2O(g)
How many moles of H2O are produced when 64.0 g C2H2 burn in oxygen?
M.M
H2O = 18.02 g/mol
C2H2 = 26.04 g/mol
2.46 moles H2O
5.13 moles H2O
4.92 moles H2O
2.00 moles H2O
Answer:
Approximately [tex]2.46\; \rm mol[/tex].
Explanation:
Make use of the molar mass data ([tex]M({\rm C_2H_2}) = 26.04\; \rm g \cdot mol^{-1}[/tex]) to calculate the number of moles of molecules in that [tex]64.0\; \rm g[/tex] of [tex]\rm C_2H_2[/tex]:
[tex]\begin{aligned}n({\rm C_2H_2}) &= \frac{m({\rm C_2H_2})}{M} \\ &= \frac{64.0\; \rm g}{26.04\; \rm g\cdot mol^{-1}}\approx 2.46\; \rm mol\end{aligned}[/tex].
Make sure that the equation for this reaction is balanced.
Coefficient of [tex]\rm C_2H_2[/tex] in this equation: [tex]2[/tex].
Coefficient of [tex]\rm H_2O[/tex] in this equation: [tex]2[/tex].
In other words, for every two moles of [tex]\rm C_2H_2[/tex] that this reaction consumes, two moles of [tex]\rm H_2O[/tex] would be produced.
Equivalently, for every mole of [tex]\rm C_2H_2[/tex] that this reaction consumes, one mole of [tex]\rm H_2O[/tex] would be produced.
Hence the ratio: [tex]\displaystyle \frac{n({\rm H_2O})}{n({\rm C_2H_2})} = \frac{2}{2} = 1[/tex].
Apply this ratio to find the number of moles of [tex]\rm H_2O[/tex] that this reaction would have produced:
[tex]\begin{aligned}n({\rm H_2O}) &= n({\rm C_2H_2}) \cdot \frac{n({\rm H_2O})}{n({\rm C_2H_2})} \\ &\approx 2.46\; \rm mol \times 1 = 2.46\; \rm mol\end{aligned}[/tex].
Covalent bonded atoms make up what
Use an example of how we use an informal kind of scientific method in our everyday lives
Answer:
baking cookies
Explanation:
One example of using a scientific method is baking cookies. You make a hypothesis that you cookies will be done in 15 minutes. Then, after 15 minutes, you see that either your hypothesis was correct and you cookies are perfect or you need to bake them longer making you hypothesis incorrect. (please change the wording up a bit if you want. i tried to make it make the most sense)
Answer:
Explanation:
When you loose your phone. You try to remember where you last used your phone, and question yourself where you might have left it. If you say that you probably left it in the kitchen, that would be like your hypothesis. Then you go look for it where you thought you left it which would be your experiment. If maybe it is not there that would be like your conclusion so you would reject your hypothesis because it was wrong. Then you try the scientific method again but with a different hypothesis, like that maybe you left it in the living room. You do your experiment which is when you go look for it. In the conclusion if your hypothesis was right you accept your hypothesis. That can be an example of how we use the scientific method in our everyday lives.
Which of the following must be
TRUE if a solution is to be
considered acidic?
A. [H^+] < [OH)
B. [H^+] > [OH ]
C. KW= [H^+] /[OH]
D. [H^+] =[OH)
Answer:
c
Explanation:
kw=h+bls
10 ejemplos de disoluciones identificando el soluto y el solvente y el tipo de disolucion que corresponde
Answer:
iqjapsgvöaöqpwüsbwjwj
What is diffusion? How does the motion of gas molecules explain how a gas diffuses throughout a room?
Answer:
Diffusion in gases
Diffusion is driven by differences in concentration. When chemical substances such as perfume are let loose in a room, their particles mix with the particles of air. The particles of smelly gas are free to move quickly in all directions
Explanation:
hope this helps
Someone please help me
Answer:reflection
Explanation:
The element in group 14, period 3 of the periodic table is classified as a?
1. Metal
2. Noble gas
3. Metalloid
4. nonmetal
Answer:
It's a Metalloid
Explanation:
Which of the following elements would not be a good conductor of electricity?
sodium
iron
calcium
sulfur
Answer:
azufre
Explanation:
El azufre es un mal conductor del calor y aislante de la electricidad.
A student investigates the reaction between sodium hydroxide solution and dilute sulfuric acid.
He does a titration to find the concentration of the sulfuric acid.
(a) Give the colour change of the methyl orange indicator at the end-point.
Explanation:
the colour change will be from orange to pink
The color change of the methyl orange indicator at the end-point will show orange to pink.
What is indicator?In an acidic or basic medium, an indicator is just a material that changes color. Indicators are termed indicators because they show one color in an acidic media and different colors in a basic medium. Indicators come in a variety of shapes and sizes: Natural indicators are indicators acquired from natural sources.
It is a just a acid base reaction in which methyl orange acts as a indicator.
In this reaction, when sodium hydroxide solution and dilute sulfuric acid are reacts with each other then after using( indicator)methyl orange the color will be change form orange to pink which indicates the nature of solution will be acidic.
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An engine operates on a Carnot cycle that uses 1mole of an ideal gas as the
working substance and operates from a most compressed stage of 100 Nm and
327 K. It expands isothermally to a pressure of 90 Nm and then adiabatically to a
most expanded stage of 27 K. Calculate the AU, 9, and w for each step. Calculate
the net work done and the efficiency of the cycle [Cv,m for the gas) is 25 J/k/mol.
Answer:
Step 1;
q = w = -0.52571 kJ, ΔS = 0.876 J/K
Step 2
q = 0, w = ΔU = -7.5 kJ, ΔH = -5.00574 kJ
Explanation:
The given parameters are;
[tex]P_i[/tex] = 100 N·m
[tex]T_i[/tex] = 327 K
[tex]P_f[/tex] = 90 N·m
Step 1
For isothermal expansion, we have;
ΔU = ΔH = 0
w = n·R·T·ln([tex]P_f[/tex]/[tex]P_i[/tex]) = 1 × 8.314 × 600.15 × ln(90/100) = -525.71
w ≈ -0.52571 kJ
At state 1, q = w = -0.52571 kJ
ΔS = -n·R·ln([tex]P_f[/tex]/[tex]P_i[/tex]) = -1 × 8.314 × ln(90/100) ≈ 0.876
ΔS ≈ 0.876 J/K
Step 2
q = 0 for adiabatic process
ΔU = 25×(27 - 327) = -7,500
w = ΔU = -7.5 kJ
ΔH = ΔU + n·R·ΔT
ΔH = -7,500 + 8.3142 × 300 = -5,005.74
ΔH = ΔU = -5.00574 kJ
If you react 156.0 g of calcium chloride with an excess NaOH, how much sodium chloride should you get?
Answer:
164.3g of NaCl
Explanation:
Based on the chemical equation:
CaCl2 + 2NaOH → 2NaCl + Ca(OH)2
where 1 mole of CaCl2 reacts with 2 moles of NaOH
To solve this question we must convert the mass of CaCl2 to moles. Using the chemical equation we can find the moles of NaCl and its mass:
Moles CaCl2 -Molar mass: 110.98g/mol-
156.0g CaCl₂ * (1mol / 110.98g) = 1.4057 moles CaCl2
Moles NaCl:
1.4057 moles CaCl2 * (2mol NaCl / 1mol CaCl2) = 2.811 moles NaCl
Mass NaCl -Molar mass: 58.44g/mol-
2.811 moles NaCl * (58.44g / mol) = 164.3g of NaCl
How do I calculate the pOH of a Solution at 25℃ with a [OH-1] = 6.5 x 10-9 M and state whether the Solution is Acidic, Basic, or Neutral?
Answer:
pOH = 8.19
Acidic solution (pH < 7.0)
Explanation:
The pOH of the solution is defined as:
pOH = - log [OH⁻]
Since we have [OH⁻] = 6.5 x 10⁻⁹ M, we calculate the pOH as follows:
pOH = - log (6.5 x 10⁻⁹) = 8.19
To know if the solution is acidic, neutral or basic, we have to calculate the pH from the value of pOH:
pH + pOH = 14
⇒ pH = 14 - pOH = 14 - 8.19 = 5.81
The solution is acidic because pH < 7.0.
Global climate change is a result of human activity?
Answer:
Yes
Explanation:
Due to pollution, greenhouse gasses, etc
Humans are increasingly influencing the climate and the earth's temperature by burning fossil fuels, cutting down forests and farming livestock. This adds enormous amounts of greenhouse gases to those naturally occurring in the atmosphere, increasing the greenhouse effect and global warming.
What type of reaction is Al + KOH +H2O = K[Al(OH)4] + H2
Answer:
Al + 2 KOH + 6 H 2O → 3 H 2 + 2 K[Al(OH) 4] This is a complexation reaction: K[Al(OH) 4] is the formed complex. ; Silvery-white, malleable, ductile, odorless metal.
Explanation:
I hope this help
is the following chemical equation balanced? Please make a claim, provide evidence, and then explain
your reasoning
2Li + 2H2O → H2 + 2LIOH
I NEED HELP WITH CHEM PLEASE HAVE A DECENT ANSWER
Answer:
x is HCl because pH = 2 (acid and it reacted with Mg plus it turned litmus paper to red)
y is NaOH because pH = 10 (base and turned litmus paper to blue)
z is NaCl because pH = 7 (neutral and no reaction to litmus paper and Mg)
why metal in the middle of metal activity series can't be obtained by heating ors in air please help me I will give u branist.follow u back and give u like plz help me with a good answer
[tex]\huge\mathsf{\red{\underline{\underline{Answer}}}}[/tex]
[tex]{\green{\dashrightarrow}}[/tex]Metals such as iron, zinc, lead, copper, etc., are in the middle of the reactivity series. These are moderately reactive metals and are usually present as sulphides or carbonates. A metal is obtained from its ore by the processes of reduction or by electrolysis.
A Cartesian Diver demonstrates which of the following?
A. the inverse relationship of Boyle's law
B. the direct relationship of Boyle's law
C. squeezing the bottle, pushes the test tube down.
D. the density of a gas is less than the density of water.
Answer:
(a) The inverse relationship of Boyle's law.
Explanation:
A Cartesian diver is used in scientific experiments to demonstrate the certain principles in science such as;
i. The principle of floatation or the Archimedes' principle.
ii. The implication of the ideal gas law as seen in, for example, Boyle's law and pressure law,
iii. Pascal's principle.
The diver demonstrates that given a large soft drink bottle containing water and a medicine dropper at its top, squeezing the bottle pushes the dropper down to the bottom. When the squeezing stops, the dropper comes back to the top again.
Now using this to demonstrate Boyle's law (which shows the relationship between pressure and volume where increase in one results in the decrease in the other), when the bottle is squeezed (which means pressure is increased on the bottle), the water is forced into the medicine dropper thereby decreasing the volume of air in the dropper. Removing pressure on the bottle produces an opposite effect.
How did Rutherford's work help form the present-day model of the atom?
Answer:
Rutherford overturned Thomson's model in 1911 with his well-known gold foil experiment in which he demonstrated that the atom has a tiny and heavy nucleus.
Explanation:
Rutherford designed an experiment to use the alpha particles emitted by a radioactive element as probes to the unseen world of atomic structure.
Energy that is made from the power of moving water
a
b
ОООО
wind
hydroelectric
coal
с
d
biomass
Hydroelectric energy is produced.
chemical formula for diethyl ester dimethyl ammonium chloride
-PLEASE HELP ASAP
Predict the total pressure in Container C if the initial pressure in
Container A was tripled and Container B was reduced by one-third then
mixed together in Container C.
SHOW ALL WORK
Answer:
[tex]98 \times x6x \geqslant {36461 { {3 \frac{ \sqrt[ |?| ]{?} }{?} }^{2} }^{?} }^{2} [/tex]
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