Which equation shows x^2+6x-2 = 0 rewritten by completing the square?

A. (x+3)^2=18
B. (x+3)^2-11
C. (x+3)^2-2
D. (X+3)^2-9

Answers

Answer 1

Answer:

Option B.

Step-by-step explanation:

We have the equation:

x^2 + 6*x - 2 = 0

Remember that:

(a*x + b)^2 = (a*x)^2 + 2*a*b*x + b^2

Because the term with x^2 has a coefficient equal to 1, then a = 1.

(x + b)^2 = x^2 + 2*b*x + b^2

The ter with x is: 6*x

then:

2*b*x = 6*X

2*b = 6

b = 6/2 = 3

we have:

(x + 3)^2 = x^2 + 6*x + 9

Now, our equation is:

x^2 + 6*x - 2 = 0

Now we can add the term (11 - 11) = 0

x^2 + 6*x - 2 + (11 - 11) = 0

x^2 + 6*x - 2 + 11 - 11 = 0

x^2 + 6*x + (11 - 2) - 11 = 0

x^2 + 6*x + 9 - 11 = 0

And we know that:

x^2 + 6*x + 9  = (x + 3)^2

Then we can rewrite our equation as:

(x + 3)^2 - 11 = 0

Then the correct option is B.

Answer 2

The equation that matches our result is option B. (x+3)² - 11. Therefore, rewriting x² + 6x - 2 = 0 by completing the square gives us (x+3)² - 11 = 0.

To rewrite the equation x² + 6x - 2 = 0 by completing the square, we need to follow these steps:

Move the constant term (-2) to the other side of the equation:

x² + 6x = 2

Take half of the coefficient of x (which is 6) and square it. Add the result to both sides of the equation:

x² + 6x + (6/2)² = 2 + (6/2)²

x² + 6x + 9 = 2 + 9

x² + 6x + 9 = 11

Now, let's look at the answer choices:

A. (x+3)² = 18

B. (x+3)² - 11

C. (x+3)² - 2

D. (x+3)² - 9

Among the answer choices, the equation that matches our result is option B. (x+3)² - 11. Therefore, rewriting x² + 6x - 2 = 0 by completing the square gives us (x+3)² - 11 = 0.

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Answers

Answer:

Y ≈ 59.0°

Step-by-step explanation:

Using the Cosine rule

cosY = [tex]\frac{x^2+z^2-y^2}{2xz}[/tex]

with x = 22, y = 20, z = 18

cosY = [tex]\frac{22^2+18^2-20^2}{2(22)(18)}[/tex]

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Answers

9514 1404 393

Answer:

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Step-by-step explanation:

There are a couple of ways to do this. We can find YZ using the Pythagorean theorem, or we can find it using trig functions.

We know from SOH CAH TOA that ...

  Cos = Adjacent/Hypotenuse

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__

The length of side YZ can be found from ...

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__

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Answers

9514 1404 393

Answer:

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Step-by-step explanation:

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is shown in the attachment. It is found by multiplying the equation on the left by the inverse of the coefficient matrix.

  [tex]\left[\begin{array}{c}x\\y\end{array}\right] =\left[\begin{array}{c}4\\5\end{array}\right][/tex]

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Answers

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Answers

Answer:

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Answers

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Step-by-step explanation:

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