which landform was most affected by erosion (had the most sediment displaced)? why? answer in 2–3 complete sentences.

When the image of an object is seen in a plane mirror, the distance from the mirror to the image depends on the distance from the object to the mirror.

It is because a Plane Mirror is the incident ray, the reflected ray, and the normal to the surface all lie in the same plane, and the angle of incidence is equal to the angle of reflection. So, the distance from the object to the mirror equals the distance from the image to the mirror. Thus whoever the person viewing this image must sight at this image location.

Answer:

25 seconds

Explanation:

500/20

I believe the answer would be B.solids.

Explanation:

Hope this helped!

In solids these can convection not occur and convection can occur in both liquids and gases, as they are both considered fluids. Thus, option B is correct.

However, convection cannot occur in solids, as the particles in solids are generally fixed in position and do not have the freedom to move and transfer heat through bulk motion as in convection.

A solid is one of the three fundamental states of matter, along with liquids and gases. It is characterized by having a definite shape and volume. Solids are composed of tightly packed particles, such as atoms, molecules, or ions, that are held together by strong intermolecular forces.

These particles vibrate in fixed positions but do not have the ability to move freely throughout the substance. As a result, solids maintain their shape and volume under normal conditions and exhibit relatively low compressibility compared to gases and liquids. Examples of solids include metals, rocks, wood, plastics, and ice.

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From the given data the focal distance for the given concave mirror is +30 cm.

The focal distance, f, for a concave mirror, can be determined using the mirror formula:

1/f = 1/v - 1/u

Where:

f is the focal distance,

v is the image distance,

u is the object distance.

In this case, the object distance, u, is given as +15 cm (in front of the mirror), and the image distance, v, is given as +30 cm (in front of the mirror). We can substitute these values into the mirror formula:

1/f = 1/30 - 1/15

Simplifying the equation, we get:

1/f = (2 - 1) / 30

1/f = 1/30

f = 30 cm

Therefore, the focal distance, f, for this concave mirror is O +30 cm.

In conclusion, the focal distance for the given concave mirror is +30 cm.

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Approximately 6.375 seconds pass before the magnetic field disappears completely.

To find the change in time (Δt) it takes for the magnetic field to drop to zero, we can use Faraday's law of electromagnetic induction.

Faraday's law states that the induced electromotive force (EMF) in a loop of wire is equal to the rate of change of magnetic flux through the loop. Mathematically, it can be expressed as:

[tex]\begin{equation}EMF = -\frac{d\Phi}{dt}[/tex]

Where:

EMF is the electromotive force (voltage)

[tex]\frac{d\Phi}{dt}[/tex] is the rate of change of magnetic flux

In this case, the induced current in the loop is 0.20 A. We can use Ohm's law to relate the current, resistance, and voltage:

EMF = I * R

Where:

I is the current (0.20 A)

R is the resistance (0.038 ohms)

Since the magnetic field is reducing at a constant rate, we can assume that the rate of change of magnetic flux is constant.

The magnetic flux (Φ) through the loop is given by:

Φ = B * A

Where:

B is the magnetic field (1.8 T)

A is the area of the loop (π * r²)

Substituting the values:

Φ = (1.8 T) * (π * (0.03 m)²)

  = 0.051 m² * T

Now, we can equate the two equations for EMF:

[tex]\begin{equation}EMF = -\frac{d\Phi}{dt}[/tex]

[tex]\begin{equation}I \cdot R = -\frac{d\Phi}{dt}[/tex]

Rearranging for dt:

[tex]\begin{equation}dt = -\frac{d\Phi}{I \cdot R}[/tex]

Substituting the values:

[tex]\begin{equation}dt = -\frac{0.051\text{ m}^2 \cdot T}{0.20\text{ A} \cdot 0.038\text{ ohms}}[/tex]

 [tex]\begin{equation}= -\frac{0.051}{0.008\text{ s}}[/tex]

  = -6.375 s

The negative sign indicates that the time is decreasing. However, we are interested in the magnitude of the time, so we can take the absolute value:

Δt = |dt| = 6.375 s

Therefore, the change in time it takes for the magnetic field to drop to zero is approximately 6.375 seconds.

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The correct answer is Option a. The angle of friction, Ø', can be determined using the formula:

Ø' = tan^(-1)(τ'/σn)

where Ø' is the angle of friction, τ' is the shear stress, and σn is the normal stress. In this case, the shear stress can be calculated by dividing the shear force at failure (300 N) by the area of the specimen. The area is the product of the specimen's height (25 mm) and its average perimeter [(2 * 63 mm) + (2 * 25 mm)].

Ø' = tan^(-1)(300 N / (25 mm * [(2 * 63 mm) + (2 * 25 mm)]) / 105 kN/m^2

Simplifying the equation:

Ø' = tan^(-1)(0.0256) ≈ 1.47°

b. To determine the shear force required to cause failure for a normal stress of 180 kN/m^2, we can use the formula:

τ' = Ø' * σn

Given Ø' = 1.47° and σn = 180 kN/m^2:

τ' = 1.47° * 180 kN/m^2 = 2.646 kN/m^2

c. The principal stresses at failure can be calculated using the equation:

σ1 = σn + τ'
σ3 = σn - τ'

Given σn = 180 kN/m^2 and τ' = 2.646 kN/m^2:

σ1 = 180 kN/m^2 + 2.646 kN/m^2 = 182.646 kN/m^2
σ3 = 180 kN/m^2 - 2.646 kN/m^2 = 177.354 kN/m^2

d. The pole on the Mohr's circle represents the average normal stress (σn) and is located at (σn, 0). Since σn = 180 kN/m^2, the pole would be located at (180 kN/m^2, 0).

To find the angle of inclination of the major and minor principal plane with the horizontal, we can use the equation:

θ = (1/2) * tan^(-1)((2 * τ') / (σ1 - σ3))

Given τ' = 2.646 kN/m^2, σ1 = 182.646 kN/m^2, and σ3 = 177.354 kN/m^2:

θ = (1/2) * tan^(-1)((2 * 2.646 kN/m^2) / (182.646 kN/m^2 - 177.354 kN/m^2))

Simplifying the equation:

θ ≈ 1.05°

Therefore, the angle of inclination of the major and minor principal plane with the horizontal is approximately 1.05°.

In conclusion, the angle of friction (Ø') is approximately 1.47°. For a normal stress of 180 kN/m^2, the shear force required to cause failure is approximately 2.646 kN/m^2. The principal stresses at failure for this condition are σ1 = 182.646 kN/m^2 and σ3 = 177.354 kN/m^2. The pole on the Mohr's circle is located at (180 kN/m^2, 0), and the angle of inclination of the major and minor principal plane with the horizontal is approximately 1.05°.

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Answer:

6 m/s

Explanation:

momentum= mass times velocity

120 = 20v

v = 120/20

Answer:

7

Explanation:

7

Answer:

The two types of waves are longitudinal and transverse

Explanation:

hope it helped! and i hope its correct

As the temperature increases, the kinetic energy of the molecules also increases.

The relationship between the kinetic energy of molecules in an object and the object's temperature is that as the temperature increases, the kinetic energy of the molecules also increases.

This relationship is governed by the kinetic theory of gases, which states that the temperature of a gas is directly proportional to the average kinetic energy of its molecules.

Temperature is a measure of the average kinetic energy of the particles in a substance. When the temperature of an object increases, the molecules within it gain more energy and move faster.

As a result, their kinetic energy increases. Conversely, when the temperature decreases, the molecules lose energy and their kinetic energy decreases.

The kinetic energy of a molecule is directly related to its mass and velocity. As the temperature increases, the molecules move with greater speed and collide more frequently with each other and the walls of their container.

These collisions transfer energy, leading to an overall increase in kinetic energy.

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Answer:

1) A,B,F,G

2)B,D,E

3) A,C,F,G

Explanation:

Answer: Sea otter is the pioneer species in the kelp forest as it regulates and controls the population of other species in the kelp forest.

Explanation:

If sea otters are hunted and their population is brought to extinction then this will cause major harm the ecosystem of the kelp forest and it will disturb the ecological balance in the kelp forest. The herbivorous animals consumed by the sea otters will increase in population and they will consume a lot of vegetation in the forest. The kelp forest which forms the coastline will not remain effective in providing protection against the storms to the neighboring areas.

A height of about 34,184.49 meters is required for the block of ice to totally melt upon impact.

To determine the height necessary for the block of ice to completely melt upon impact, we need to equate the gravitational potential energy to the energy required to melt the ice.

The gravitational potential energy is given by the formula:

PE = m * g * h

Where PE is the gravitational potential energy, m is the mass of the ice, g is the acceleration due to gravity, and h is the height.

The energy required to melt the ice is the product of the mass of the ice and its heat of fusion (Lf = 335,000 J/kg). Therefore, the energy required to melt the ice is:

E = m * Lf

By equating the gravitational potential energy to the energy required to melt the ice, we have:

m * g * h = m * Lf

The mass of the ice cancels out on both sides, leaving:

g * h = Lf

Now we can solve for the height h:

[tex]\begin{equation}h = \frac{Lf}{g}[/tex]

Substituting the values:

Lf = 335,000 J/kg

g = 9.8 m/s²

h = 335,000 J/kg / 9.8 m/s²

Calculating the height h:

h ≈ 34,184.49 meters

Therefore, the height necessary for the block of ice to completely melt upon impact is approximately 34,184.49 meters.

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The ground state electron configurations for the molecules are:

Oxygen (O2): σ2s^2 σ*2s^2 σ2p^4 π2p^2

Nitrogen (N2): σ2s^2 σ*2s^2 σ2p^3 π2p^2

To determine the ground state electron configurations of the molecules using molecular orbital theory, we need to consider the molecular orbital diagram and the electron filling order.

Oxygen (O2):

The atomic configuration of oxygen is 1s^2 2s^2 2p^4. In molecular oxygen (O2), we combine the atomic orbitals to form molecular orbitals. The molecular orbital diagram for O2 is as follows:

The filling order for molecular orbitals is as follows: σ2s < σ2s < σ2p < π2p < π2p < σ*2p. According to Hund's rule, each orbital should be singly filled before pairing occurs.

The electron configuration for O2 can be obtained by filling the molecular orbitals with the valence electrons from each oxygen atom:

σ2s^2 σ*2s^2 σ2p^4 π2p^2

Nitrogen (N2):

The atomic configuration of nitrogen is 1s^2 2s^2 2p^3. In molecular nitrogen (N2), we combine the atomic orbitals to form molecular orbitals. The molecular orbital diagram for N2 is as follows:

The filling order for molecular orbitals is the same as in the case of oxygen: σ2s < σ2s < σ2p < π2p < π2p < σ*2p.

The electron configuration for N2 can be obtained by filling the molecular orbitals with the valence electrons from each nitrogen atom:

σ2s^2 σ*2s^2 σ2p^3 π2p^2

Using molecular orbital theory, we determined the ground state electron configurations for the molecules as follows:

Oxygen (O2): σ2s^2 σ*2s^2 σ2p^4 π2p^2

Nitrogen (N2): σ2s^2 σ*2s^2 σ2p^3 π2p^2

Please note that the electron configurations obtained through molecular orbital theory represent the ground state electronic distribution based on the available orbitals and their energy levels.

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The purple arrow on the graph that shows speed and direction, this arrow called B. a vector.

Vectors have magnitude (size) and direction. They are represented graphically as arrows, in which the direction of the arrow denotes the direction of the vector, while the length of the arrow represents the vector's magnitude (size). Furthermore, the term "vector" is used in physics to refer to a quantity that has both magnitude and direction, such as velocity, force, and acceleration.

They are essential in physics since they enable scientists to precisely describe how objects move and interact. Moreover, vector quantities, such as velocity and force, are often depicted with arrows in physics diagrams, with the direction of the arrow representing the vector's direction and the arrow's length representing its magnitude. The use of vectors in physics and other fields has made a significant contribution to the advancement of science and technology. So therefore the correct answer is B. a vector, the purple arrow on the graph that shows speed and direction.

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In a pig-calling contest, the caller produces a sound with an intensity level of 87 dB.  Understanding the intensity level of the sound helps evaluate its potential impact on the surrounding environment and human hearing.

The intensity level of a sound is a measure of its loudness and is expressed in decibels (dB). The decibel scale is logarithmic, meaning that each increase of 10 dB represents a tenfold increase in sound intensity.

To calculate the intensity level in decibels, we use the formula:

dB = 10 * log10(I/I₀)

where I is the sound intensity and I₀ is the reference intensity (typically the threshold of hearing, which is approximately 10^(-12) W/m^2).

Given that the intensity level is 87 dB, we can rearrange the formula to solve for I:

87 = 10 * log10(I/I₀)

8.7 = log10(I/I₀)

I/I₀ = 10^(8.7)

I = (10^(8.7)) * I₀

In the pig-calling contest, the caller produces a sound with an intensity level of 87 dB. The calculation of the sound intensity requires knowledge of the reference intensity and the logarithmic relationship of the decibel scale.

By using the formula and considering the logarithmic nature of the scale, we can determine the actual sound intensity. Remember that the decibel scale is logarithmic, so even a small increase in decibels represents a significant increase in sound intensity. Understanding the intensity level of the sound helps evaluate its potential impact on the surrounding environment and human hearing.

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Answer:

Ferromagnetism is a kind of magnetism that is associated with iron, cobalt, nickel, and some alloys or compounds containing one or more of these elements. It also occurs in gadolinium and a few other rare-earth elements.

Explanation:

Hope this helped Mark BRAINLIEST!!!

a. u is harmonic for let u(x, y) = xy because ∂²u/∂x² + ∂²u/∂y² = 0.

b. A harmonic conjugate of u is v = (x² - y²)/2.

To determine that u is harmonic, we need to verify whether u satisfies Laplace's equation or not. Laplace's equation is given by:

∂²u/∂x² + ∂²u/∂y² = 0

On differentiating u(x, y) = xy partially, we get,

∂u/∂x = y∂u/∂y = x

On differentiating partially again, we get,

∂²u/∂x² = 0∂²u/∂y² = 0

Therefore, ∂²u/∂x² + ∂²u/∂y² = 0

Thus, u is harmonic.

To find a harmonic conjugate of u, we need to find v(x, y) such that u + iv is analytic. In other words, v must satisfy the Cauchy-Riemann equations. The Cauchy-Riemann equations are given by:

∂u/∂x = ∂v/∂y∂u/∂y = -∂v/∂x

On substituting u = xy in the above equations, we get,

∂v/∂y = x∂v/∂x = -y

On integrating the above equations, we get

v = (x² - y²)/2 + C

Thus, a harmonic conjugate of u is v = (x² - y²)/2.

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The particle remains stationary in a downward-directed electric field, the charge must be negative to balance the gravitational force.

The two forces acting on the particle are the gravitational force and the electric force. The gravitational force is given by F_gravity = m * g, where m is the mass of the particle and g is the acceleration due to gravity (9.81 m/s^2). The electric force is given by F_electric = q * E, where q is the charge of the particle and E is the magnitude of the electric field.

For the particle to remain stationary, the electric force must exactly balance the gravitational force, i.e., F_electric = F_gravity. Therefore, we can equate the two expressions and solve for the charge.m * g = q * E

Given that the mass of the particle is 1.46 g (0.00146 kg) and the magnitude of the electric field is 630 N/C, we can substitute these values into the equation:0.00146 kg * 9.81 m/s^2 = q * 630 N/C

Solving for q, we have:
q = (0.00146 kg * 9.81 m/s^2) / 630 N/C ≈ 2.262 x 10^-5 C.

Therefore, the charge of the particle must be approximately 2.262 x 10^-5 C. Since the particle remains stationary in a downward-directed electric field, the charge must be negative to balance the gravitational force.

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The relative speeds of the two objects at the bottom of the incline will be zero.

In segment 1, the object is released from rest at the top of an inclined plane. As it rolls down the incline, the potential energy is converted into both kinetic energy and rotational energy.

Assuming no slipping occurs, the object's linear velocity increases while its angular velocity remains constant.

During segment 2, where no frictional force is exerted, there are no external forces acting on the object. As a result, there is no change in the object's kinetic energy or angular velocity. Therefore, the object's linear velocity remains constant.

At the bottom of the incline, both objects will have the same linear velocity. Since they are identical objects, the relative speed between them will be zero.

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--The complete Question is, For another identical object initially at rest, no frictional force is exerted during segment 2. If the first object is released from rest at the top of an inclined plane in segment 1, and both objects roll down the incline, what will be the relative speeds of the two objects at the bottom of the incline?--

At the lowest point of its circular path, the book experiences three distinct forces: the gravitational force (downward), the normal force (upward), and the centripetal force (toward the center of the circular path).

At the lowest point of the circular path, the book is moving only in the horizontal direction. This means that the book has no vertical acceleration since its velocity in the vertical direction remains constant. According to Newton's second law, when there is no vertical acceleration, the net vertical force must be zero.

The gravitational force acts downward, pulling the book toward the center of the Earth. The normal force, exerted by the surface supporting the book, acts upward and balances the gravitational force. These two forces have equal magnitudes and opposite directions, resulting in a net vertical force of zero.

Therefore, at the lowest point of its circular path, the book experiences no net vertical force. The cancellation of the gravitational force and the normal force allows the book to move in a centripetal force circular path with only horizontal motion.

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Answer:

III. The lift force is present because the pressure across the top is less than the pressure across the bottom of the wing.

Explanation:

The wavelength of the wave is 20π/0.30 meters, which simplifies to approximately 209.44 meters.

The period of the wave is 2π/0.90 seconds, which simplifies to approximately 6.98 seconds.

The wave speed is given by the ratio of the wavelength to the period, which is approximately 29.97 meters per second.

To find the instantaneous velocity of a particle at position 0 at time 22 seconds, we differentiate the displacement equation with respect to time and evaluate it at the given time and position.

The derivative of y(x,t) with respect to t is 0.25(0.90)sin(0.30x - 0.90t + π/3). Plugging in x = 0 and t = 22, we find the instantaneous velocity to be approximately 0.177 m/s in the positive direction.

The given wave equation is y(x,t) = 0.25cos(0.30x - 0.90t + π/3), where x represents the position and t represents the time. The coefficient of x, 0.30, corresponds to the angular wave number (k) of the wave.

The coefficient of t, -0.90, corresponds to the angular frequency (ω) of the wave. By comparing the equation with the general form y(x,t) = Acos(kx - ωt + φ), we can identify the values for k and ω.

The wavelength (λ) of a wave is given by λ = 2π/k. In this case, k = 0.30, so the wavelength is 2π/0.30, which simplifies to approximately 209.44 meters.

The period (T) of a wave is given by T = 2π/ω. In this case, ω = -0.90, so the period is 2π/(-0.90), which simplifies to approximately 6.98 seconds.

The wave speed (v) is the ratio of the wavelength to the period, v = λ/T. Substituting the values, we get v = (2π/0.30) / (2π/(-0.90)), which simplifies to approximately 29.97 meters per second.

To find the instantaneous velocity of a particle at position 0 at time 22 seconds, we differentiate the displacement equation with respect to time.

The derivative of cos(0.30x - 0.90t + π/3) with respect to t is -0.90sin(0.30x - 0.90t + π/3).

Plugging in x = 0 and t = 22, we find the instantaneous velocity to be approximately 0.177 m/s in the positive direction.

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If a meteorite collides head-on with Mars and becomes buried under Mars's surface, the elasticity of this collision would be a d)perfectly inelastic collision.

The elasticity of the collision is a measure of how much energy is lost during the collision. In a perfectly inelastic collision, all of the kinetic energy of the meteorite would be converted to other forms of energy such as heat, sound, and deformation of the planet's surface. This would result in a large crater on the surface of Mars and the meteorite would be buried under the planet's surface.

A perfectly inelastic collision is a collision where two objects stick together after the collision and move as one. During a perfectly inelastic collision, the kinetic energy of the colliding objects is lost due to the deformation of the objects and the generation of heat. The velocity of the objects after the collision is less than the velocity of the objects before the collision.

In conclusion, if a meteorite collides head-on with Mars and becomes buried under Mars's surface, it would be a perfectly inelastic collision because all of the kinetic energy of the meteorite would be lost during the collision. This would result in a large crater on the surface of Mars and the meteorite would be buried under the planet's surface. The correct option is (d).

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Benedict’s test is a chemical test used to detect the presence of reducing sugars. This test is particularly used to check the presence of glucose in the urine to determine the presence of diabetes. Benedict's test is carried out by adding Benedict's reagent to the test solution and heating the mixture.

Benedict’s reagent is a blue solution made up of sodium citrate, sodium carbonate, and copper sulfate. The reaction results in the reduction of copper ions to copper oxide which is red or yellow in color. The presence of reducing sugars in the sample causes the colour of the solution to change from blue to green, yellow, orange, or red depending on the amount of reducing sugar present. A positive Benedict's test appears as green, yellow, orange, or red, whereas a negative Benedict's test appears as blue. The intensity of the colour varies based on the amount of reducing sugar present. The higher the amount of reduced sugar, the more intense the colour change.

Therefore, a positive Benedict's test shows the presence of reducing sugar while a negative Benedict's test shows the absence of reducing sugar. Benedict's test can be used to distinguish between reducing and non-reducing sugars, which are carbohydrates that are capable of reducing copper ions and those that are not.

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The x-component of the net-force acting on the radio-controlled model airplane is given by the expression -1.5 kg·m/s^2 * t.

The x-component of the net force (F_x) on an object can be calculated using Newton's second law, which states that the net force is equal to the rate of change of momentum:

F_x = dp_x/dt

Given that the momentum of the airplane is [(−0.75kg·m/s^3)t^2 (3.0kg·m/s)]i^, we can find the x-component of the momentum (p_x) as the coefficient of the i^ unit vector. Taking the derivative of p_x with respect to time (t), we obtain the x-component of the net force:

F_x = d/dt [(−0.75kg·m/s^3)t^2] = (-0.75kg·m/s^3) * 2t

Simplifying the expression, we find:

F_x = -1.5 kg·m/s^2 * t

Therefore, the x-component of the net force on the airplane is -1.5 kg·m/s^2 * t.

The x-component of the net force acting on the radio-controlled model airplane is given by the expression -1.5 kg·m/s^2 * t, where t is the time in seconds. This equation represents the rate of change of the x-component of the momentum with respect to time.

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The magnitude οf the magnetic fοrce that acts οn a 3.17 m length οf either wire is 0.0405 Newtοns.

Magnetic fοrce refers tο the fοrce exerted οn a charged particle οr a current-carrying cοnductοr due tο the presence οf a magnetic field.

F = (μ₀ * I₁ * I₂ * L) / (2π * d)

Given:

I₁ = 1.71 A

I₂ = 4.67 A

L = 3.17 m

d = 9.03 cm = 0.0903 m

After applying the formula to the supplied values, we get:

F = (4π × 10⁻⁷ T·m/A) * (1.71 A) * (4.67 A) * (3.17 m) / (2π * 0.0903 m)

Simplifying the expressiοn:

F ≈ 4π × 10⁻⁷ * 1.71 * 4.67 * 3.17 / 2 * 0.0903

F ≈ 0.0405 N

Therefοre, the magnitude οf the magnetic fοrce that acts οn a 3.17 m length οf either wire is 0.0405 Newtοns.

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Answer: Atoms that lose electrons acquire a positive charge as a result because they are left with fewer negatively charged electrons to balance the positive charges of the protons in the nucleus. Positively charged ions are called cations. Most metals become cations when they make ionic compounds.

Explanation: hope this helps