Which one is false ????

y=360

Step-by-step explanation:

y goes up by 30 everytime and would start at 30 if X =1, so X x 30= y. 12 x 30= 360=y

Answer:

300 or B

Step-by-step explanation: give the other person brainliest

Answer:

[tex](x +9)(x+2)[/tex]

Step-by-step explanation:

Given the problem,

[tex]x^2 + 11x + 18[/tex]

Factor the problem. Find factors of (18) such that when added the result is (11).

[tex](x +9)(x+2)[/tex]

Test by distributing, multiply each term in one parenthesis by every term in the other parenthesis,

[tex](x+9)(x+2)\\\\x^2 + 2x + 9x + 18\\\\x^2 + 11x + 18[/tex]

Answer:

(x+9)(x+2) is your answer

Step-by-step explanation:

x2+ 11x+ 18

x²+9x+2x+18

x(x+9)+2(x+9)

(x+9)(x+2)

Answer:

When an equation in one variable is solved using a system of equations, the solution is always the x-coordinate of each intersection.

Step-by-step explanation:

Answer:

1st part: X Coordinate

2nd part: A and C

Step-by-step explanation:

https://courses.lumenlearning.com/prealgebra/chapter/using-properties-of-angles-to-solve-problems/#:~:text=We%20measure%20angles%20in%20degrees,they%20are%20called%20supplementary%20angles.

Answer: do you mean how to find the degree?

Step-by-step explanation:

Count the number of sides in the polygon.

Find the total measure of all of the interior angles in the polygon

Divide the total measure of all of a regular polygon's angles by the number of its angles.

Subtract the sum of the known angles from the total measure of the angles for an irregular polygon.

it really depends

Answer:

∠b = 64°

Step-by-step explanation:

We know that a complete rotation is 360°, so:

∠b + 57° + 239° = 360°

∠b = 360° - 57° - 239°

∠b = 64°

Answer:

The difference is [tex]\frac{3}{8}[/tex] mile

Step-by-step explanation:

The question is incomplete, as the line plot is not attached.

I will answer this question with the attached line plot.

From the question:

[tex]Joaquin = \frac{3}{4}[/tex]

From the attached line plot:

[tex]Least = \frac{3}{8}[/tex]

The difference (D) is:

[tex]D = Joaquin - Least[/tex]

[tex]D = \frac{3}{4} - \frac{3}{8}[/tex]

Take LCM

[tex]D = \frac{6 - 3}{8}[/tex]

[tex]D = \frac{3}{8}[/tex]

Hence: The difference is [tex]\frac{3}{8}[/tex] mile

Answer: A and D

Step-by-step explanation:

if he earns $8 an hour and he got $168 and h= the hours then

h=8 x 21 = 168

Answer:

The other person is correct.

Step-by-step explanation:

Answer:

1/36

Step-by-step explanation:

P(rolling a 3) and P(rolling a 4)

= 1/6 and 1/6

=(1/6)(1/6)

=1/36

Answer:

28pi*66/360

Step-by-step explanation

Used the equation Central angle/360*2pi r

Answer:

Top left triangle has the greatest area

Step-by-step explanation:

Area of a triangle:

area = base × height / 2

a = bh/2

Top Left Triangle:

a = 6 × 5.2 / 2

a = 31.2 / 2

a = 15.6

Top Right Triangle:

a = 8 × 2.9 / 2

a = 23.2 / 2

a = 11.6

Bottom Left Triangle:

a = 2 × 7.9 / 2

a = 15.8 / 2

a = 7.9

Compare areas:

15.6 > 11.6 > 7.9

Answer:

Question 11:

[tex]\angle DAC = 53^\circ[/tex]

[tex]\angle AED = 90^\circ[/tex]

[tex]\angle ADC = 74[/tex]

[tex]DB = 16[/tex]

[tex]AE = 6.03[/tex]

[tex]AC = 12.06[/tex]

Question 12:

[tex]\triangle ABD[/tex], [tex]\triangle BAC[/tex], [tex]\triangle CDA[/tex] and [tex]\triangle DAB[/tex]

Question 13:

AC and BD are perpendicular lines, and they are diagonals

Step-by-step explanation:

Question 11

Given

[tex]\angle BAC = 53^\circ[/tex]

[tex]DE = 8[/tex]

See attachment for Rhombus

Required

Determine the indicated sides

Solving (a): [tex]\angle DAC[/tex]

Diagonal CA divides [tex]\angle DAB[/tex] into 2 equal angles

i.e

[tex]\angle DAC = \angle BAC[/tex]

So:

[tex]\angle DAC = 53^\circ[/tex]

Solving (b): [tex]\angle AED[/tex]

The angles at E is 90 degrees because diagonals AC and BD meet at a perpendicular.

So:

[tex]\angle AED = 90^\circ[/tex]

Solving (c): [tex]\angle ADC[/tex]

First, we calculate [tex]\angle ADE[/tex], considering [tex]\triangle ADE[/tex]:

[tex]\angle ADE + \angle AED + \angle DAC = 180[/tex]

[tex]\angle ADE + 90 + 53 = 180[/tex]

[tex]\angle ADE + 143 = 180[/tex]

[tex]\angle ADE = -143 + 180[/tex]

[tex]\angle ADE = 37[/tex]

To calculate [tex]\angle ADC[/tex], we have:

[tex]\angle ADC = 2*\angle ADE[/tex]

[tex]\angle ADC = 2* 37[/tex]

[tex]\angle ADC = 74[/tex]

Solving (d): [tex]DB[/tex]

From the rhombus

[tex]DB = DE +EB[/tex]

Where

[tex]DE =EB[/tex]

So:

[tex]DB = 8 + 8[/tex]

[tex]DB = 16[/tex]

Solving (e): [tex]AE[/tex]

To do this we consider [tex]\triangle ADE[/tex]

Using the tan formula

[tex]tan(\angle ADE) = \frac{AE}{DE}[/tex]

[tex]\angle ADE = 37[/tex] and [tex]DE = 8[/tex]

So:

[tex]\tan(37) = \frac{AE}{8}[/tex]

[tex]AE = 8 * \tan(37)[/tex]

[tex]AE = 6.03[/tex]

Solving (f): [tex]AC[/tex]

This is calculated as:

[tex]AC = AE + EC[/tex]

Where

[tex]AE = EC[/tex]

[tex]AC = 6.03 +6.03[/tex]

[tex]AC = 12.06[/tex]

Question 12: Isosceles Triangle

In the rhombus, all 4 sides are equal;

So, the isosceles triangle are:

[tex]\triangle ABD[/tex], [tex]\triangle BAC[/tex], [tex]\triangle CDA[/tex] and [tex]\triangle DAB[/tex]

Question 13:

AC and BD are perpendicular lines, and they are diagonals

Answer:

160

Step-by-step explanation:

72x100/45. Hope this helps

Answer:

The area of a square with side length of 2 inches is 4 square inches.

The area of a circle with radius 1.2 inches is:

[tex]\pi \times (1.2) ^{2} \\ = 3.14 \times 1.44 \\ = 4.5216 \: square \: inches[/tex]

That is approximately 4.5 square inches.

Hence, the area of the square (4) is less than {<} that of the circle (4.5)!

Answer:

16.40

Step-by-step explanation:

use Pythagorean theorem

Answer:

Step-by-step explanation:

The factors are 9 and 27 are 1,3,9,27

With that, 9/27 is undoubtedly reducible to 1/3

Before now,we were told that when a number divides itself,the result is zero...now,⅜÷⅓ should give us 1 but 3/8×3/1 = 9/8 and 9/8≠1 hence,they aren't same!

Answer:

x<9

Step-by-step explanation:

isolate the x by adding 4 on both sides. then add 4+5 to get 9.

i hope this helps :)

Answer: By finding the differences between the y-values, we can determine the degree of the model for the data.

If the first difference is the same value, the model will be linear.

If the second difference is the same value, the model will be quadratic.

Step-by-step explanation:

Answer:

34 minus -6 minus= -6

Step-by-step explanation:

Answer:

2

Step-by-step explanation:

2 is non-linear because it is not a straight line

Answer:

13 inches

Step-by-step explanation:

A clarinet case is shaped like a rectangular prism the case is 8 inches tall 3 inches wide and has a volume of 312 cubic inches what is the length of the clarinet case

The volume of a rectangular prism = Length × Width × Height

Length of the rectangular prism = Volume/ Width × Height

= 312 in³/ 3 in × 8 in

= 312 in³/24 in²

= 13 in

Length = 13 inches

Answer:

8x-10 B=3x+90

Answer:

cos60⁰=3/y

y×cos60⁰=3

y=3/cos60⁰

y=3/0.5

y=6

y²=x²+3²

6²=x²+3²

36=x²+9

x²=36-9

x²=27

x=square root of 27

x=5.19

Answer:

Step-by-step explanation:

Find the measure of angle Q:

a) Find PR using the law of cosines:

Find ∠P using law of sines:

The bearing of R from P is:

b)

Find the measure of h, the distance from Q to PR:

Find the area of ΔPQR:

Answer: b = 48 c = 26 d = 106 a = 26

Step-by-step explanation:

Answer:

95% of a gallon of water, .95, or 19/20 as a fraction

Step-by-step explanation:

Answer:

[tex]b_n = \frac{2}{27} (9^n)[/tex]

Step-by-step explanation:

Given

[tex]a_1=\frac{2}{3},\ a_n=3a_{n-1}.[/tex]

Required

An explicit rule for [tex]b_1,\ b_2,\ b_3,\ \dots[/tex]

Where [tex]b_1=a_1,\ b_2=a_3,\ b_3=a_5,\ \dots[/tex]

We have:

[tex]a_1=\frac{2}{3},\ a_n=3a_{n-1}.[/tex]

Calculate a2

[tex]a_2 = 3a_{2-1}[/tex]

[tex]a_2 = 3a_1[/tex]

[tex]a_2 = 3 * \frac{2}{3}[/tex]

[tex]a_2 = 2[/tex]

Calculate a3

[tex]a_3 = 3a_{3-1}[/tex]

[tex]a_3 = 3a_2[/tex]

[tex]a_3 = 3 *2[/tex]

[tex]a_3 = 6[/tex]

Calculate a4

[tex]a_4 = 3a_{4-1}[/tex]

[tex]a_4 = 3a_3[/tex]

[tex]a_4 = 3*6[/tex]

[tex]a_4 = 18[/tex]

Calculate a5

[tex]a_5 = 3a_{5-1}[/tex]

[tex]a_5 = 3a_4[/tex]

[tex]a_5 = 3*18[/tex]

[tex]a_5 = 54[/tex]

So:

[tex]b_1=a_1,\ b_2=a_3,\ b_3=a_5,\ \dots[/tex]

[tex]a_1=\frac{2}{3}[/tex]     [tex]a_3 = 6[/tex]     [tex]a_5 = 54[/tex]

The above sequence form a geometric sequence.

Calculate common ratio (r)

[tex]r = \frac{b_3}{b_2}[/tex]

[tex]r = \frac{a_5}{a_3}[/tex]

[tex]r = \frac{54}{6}[/tex]

[tex]r = 9[/tex]

So, the explicit formula is:

[tex]b_n = b_1 * r^{n-1[/tex]

[tex]b_1=a_1[/tex], so:

[tex]b_n = a_1 * r^{n-1[/tex]

[tex]a_1=\frac{2}{3}[/tex], so:

[tex]b_n = \frac{2}{3} * 9^{n-1[/tex]

Split:

[tex]b_n = \frac{2}{3} * \frac{9^n}{9}[/tex]

[tex]b_n = \frac{2}{3*9} (9^n)[/tex]

[tex]b_n = \frac{2}{27} (9^n)[/tex]

The explicit rule is: [tex]b_n = \frac{2}{27} (9^n)[/tex]