Answer:D
Explanation: a p e x
You are riding in an elevator that is accelerating upward. Suppose you stand on a scale. The reading on the scale is __________.
a. Greater than your true weight
b. Equal to your true weight
c. Less than your true weight
d. It's impossible to determine
Answer: A
Explanation: Your body gets pulled down, causing ur body to have more weight but not mass.
A value that describes how heavy an object is and is related to the force of gravity is:
The weight of an object
Answer: B) weight
Got it right on E2020
Which Energy transformation will occur when this rubber band is let go elastic energy -chemical energy mechanical energy -electrical energy chemical energy -mechanical energy elastic energy mechanical- energy elastict
Elastic Energy - Mechanical Energy
What is matter made of
Answer: Matter is made up of atoms that also come together to form molocules. Atoms contain Electrons (Negetive), nutronons (nuaetral), and protons (positive).
A periodic wave travels from one medium to another. Which pair of variables are likely to change in the process?
A.
velocity and wavelength
OB.
velocity and frequency
Ο Ο Ο Ο
OC.
frequency and wavelength
OD.
frequency and phase
E.
wavelength and phase
Answer:
Velocity and frequency
Explanation:
If a rock hits the ground with a KE of 33,000 J, falling from a height of 10 m, what is its weight? Remember, weight is measured in newtons (N), and is equal to mass times gravity.
A. 330 N
B. 33 N
C. It can't be computed from this information
D. 3,300 N
Answer is 3,300N
Explanation
If a 28-N force causes a rock to accelerate at 4 m/s/s, what is the mass of the rock?
Answer:
7kg
Explanation:
Given parameters:
Force on the rock = 28N
Acceleration = 4m/s²
Unknown:
Mass of the rock = ?
Solution:
According to newton's second law of motion;
Force = mass x acceleration
Insert the given parameters to find the mass;
28 = mass x 4
mass = [tex]\frac{28}{4}[/tex] = 7kg
A person weighs 780N on earth. What is his mass on earth, mass on moon? What is his weight on the moon?
Answer:
79.6kg
127.5N
Explanation:
Given parameters:
Weight of the person on earth = 780N
Now, we are to find;
Mass on earth;
Mass on moon;
Weight on moon
Solution:
The mass on earth and on the moon are the same. Mass is the amount of matter in a substance.
Weight = mass x acceleration due to gravity
780 = mass x 9.8
mass = [tex]\frac{780}{9.8}[/tex] = 79.6kg
Mass on earth and moon = 79.6kg
The acceleration due to gravity on the moon is 1.6m/s²
Weight on moon = 79.6 x 1.6 = 127.5N
George got a bad grade on the test because he decided he would rather sleep than study. this is an example of a __ attribution
the right answer for this question would be dispositional
Answer:
dispositional
Explanation:
?
_2. Region surrounding the nucleus where electrons are found.
?
_3. Positively charged center of an atom.
?
4. Particles that differ in number between isotopes.
Answer:
Electron shell
Nucleus
Neutrons
Explanation:
An atom is made up of three fundamental subatomic particles which are the protons, neutrons and electrons.
Protons are the positively charged particles. Neutrons do not carry any charges. Both protons and neutrons are found in the tiny nucleus at the center of that atom. The electrons are negatively charged. They are found outside the nucleus in electronic shells.Harry is reading an online summary of the law of reflection. The site states that after light hits a mirror, the angle of reflection is the angle between the reflected ray and the normal, which is the surface of the mirror.
Which statement corrects an error on the site?
Answer:
A
Explanation:
A crane lifts a 425 kg steel beam vertically upward a distance of 614.4 m
How much work does the crane do on the beam if the beam accelerates upward at 1.8 m/s2? Neglect frictional forces.
PHYSICS
*not sure about the answer but here we go*
Mass = 425 kg
distance = 614.4 m
acceleration = 1.8 m/s²
Answer :
Count Force first.
[tex]f \: = m \: \times a[/tex]
F = 425 × 1,8
F = 765 N ✅
Now let's count Work.
[tex]w \: = \: f \: \times s[/tex]
W = 765 × 614.4
W = 470016 J ✅
Mass is sometimes described as the difficulty of acceleration of an object. How does Newton's second law agree with this description?
Answer:
Increasing force tends to increase acceleration while increasing mass tends to decrease acceleration. Thus, the greater force on more massive objects is offset by the inverse influence of greater mass. Subsequently, all objects free fall at the same rate of acceleration, regardless of their mass.
If the mass increases, it's harder to accelerate
Because force tends to rise with mass while mass tends to decrease with force, mass is sometimes referred to as the difficulty of accelerating an item. As a result, the greater mass's inverse effect balances out the larger force exerted on more massive objects.
Newton's second law agreement with difficulty of acceleration of an object-While acceleration tends to decrease as mass increases, it tends to increase as force increases. As a result, the bigger force acting on more massive objects is balanced off by the greater mass's inverse effect.As a result, all things fall in free fall at the same rate of acceleration regardless of mass. As the mass increases, accelerating becomes more difficult.Newton's second law of motion is applicable when there are unbalanced forces acting on an object.The second law states that an object's rate of acceleration depends on both its mass and the net force acting on it.An object's acceleration is directly proportional to the net force applied on it and inversely proportional to its mass.An object's acceleration increases as the amount of force exerted on it does.A decreasing acceleration is caused by a rise in an object's mass.The acceleration of an item caused by a net force is inversely proportional to the mass of the object and directly proportional to the magnitude of the net force in the same direction.To learn more about Newton's second law of motion click here-
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help please! thank you! please dont plagiarism my teacher checks for plagiarism ;-;
Answer:
the reason why the crate won't move to the direction of the force being applied (F app). is because the (Fgravity) is pulling it down making it heavy to move
given a circuit powered at 12V with R1, R2, R3 respectively of 10,20,30 Ohm, determine R4 in such a way that the Wheatstone bridge is in equilibrium and then calculate voltages and currents as for reference exercise.
Answer:
The balanced condition for Wheat stones bridge is
Q
P
=
S
R
as is obvious from the given values.
No, current flows through galvanometer is zero.
Now, P and R are in series, so
Resistance,R
1
=P+R
=10+15=25Ω
Similarly, Q and S are in series, so
Resistance R
2
=R+S
=20+30=50Ω
Net resistance of the network as R
1
and R
2
are in parallel
i=
R
V
=
50
6×3
=0.36 A.
Explanation:
If the speed of a roller coaster at the bottom of a hill is 20.0 m/s , what is the tallest hill the coaster can climb, assuming no friction losses ?
Answer:
20.4 meters
Explanation:
KE = 1/2 m v^2 = mgh = PE (convert all kinetic energy to potential energy, because at the highest point the coaster can climb, it will be stopped!)
=> h = (1/2 m v^2) / (mg) = v^2/(2*g) = (20 m/s)^2 / (2*9.8 m/s^2) = 20.4 m
The tallest height that the roller coaster can climb is 20 m.
A roller coaster is a device in which energy conversions from potential to kinetic energy takes place. Hence the roller coaster can easily be used to demonstrate the conversion of mechanical energy from one form to another.
Given that the velocity of the roller coaster at the bottom of the hill is 20.0 m/s, potential energy is converted into kinetic energy.
Hence;
mgh = 1/2mv^2
gh =1/2v^2
h = 1/2v^2/g
h = 0.5 × (20)^2/10
h = 20 m
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what happens at a transform boundary
Answer:
Answer is "two tectonic plates slide past eachother" ( for a pe x)
Explanation:
In Einstein’s theory of gravitation, gravity is due to:
A)the acceleration of the universe
B)the presence of mass
C)the rotation of the universe
D)the curvature of spacetime
E)the speed of light
Answer:
B, caused by the presence of mass
Explanation:
A 2 kg block slides with constant velocity along a horizontal tabletop. A horizontal applied force of 10 N and a downward applied force of 5 N act on the block, as shown. The coefficient of friction between the block and tabletop is most nearly...
Answer:
huh
Explanation:
Answer:
what are we finding?
Explanation:
Enter an expression for the force constant for the floating raft, in terms of L, g, and the density of water, ρ.
Answer:
K = ρL²g
Explanation:
Consider L as the length of the raft inside the water when the raft is displaced through additional distance y;
Then:
F = upthrust ( restoring force) = weight of the liquid displaced.
[tex]F = V_{\omega} \rho_{\omega} g= A y \rho_{\omega} g[/tex]
where;
A = L²
[tex]\rho_{\omega} = \rho[/tex]
F = ky.
Then,
[tex]Ay \rho g = ky[/tex]
[tex]L^2y \rho g = ky[/tex]
Divide both sides by y
K = ρL²g
A barge is pulled by two tugboats. If the resultant of the forces exerted by the
tugboats is 5kN force directed along the axis of the barge, determine the tension in
each of the ropes for α = 45
Answer:
Approximately [tex]3.5\; \rm kN[/tex] in each of the two ropes.
Explanation:
Let [tex]F_1[/tex] and [tex]F_2[/tex] denote the tension in each of the two ropes.
Refer to the diagram attached. The tension force in each rope may be decomposed in two directions that are normal to one another.
The first direction is parallel to resultant force on the barge.
The component of [tex]F_1[/tex] in that direction would be [tex]\displaystyle F_1\cdot \cos(45^\circ) = \frac{F_1}{\sqrt{2}}[/tex].Similarly, the component of [tex]F_2[/tex] in that direction would be [tex]\displaystyle F_2\cdot \cos(45^\circ) = \frac{F_2}{\sqrt{2}}[/tex].These two components would be in the same direction. The resultant force in that direction would be the sum of these two components: [tex]\displaystyle \frac{F_1 + F_2}{\sqrt{2}}[/tex]. That force should be equal to [tex]5\; \rm kN[/tex].
The second direction is perpendicular to the resultant force on the barge.
The component of [tex]F_1[/tex] in that direction would be [tex]\displaystyle F_1\cdot \sin(45^\circ) = \frac{F_1}{\sqrt{2}}[/tex].Similarly, the component of [tex]F_2[/tex] in that direction would be [tex]\displaystyle F_2\cdot \sin(45^\circ) = \frac{F_2}{\sqrt{2}}[/tex].These two components would be in opposite directions. The resultant force in that direction would be the difference of these two components: [tex]\displaystyle \frac{F_1 - F_2}{\sqrt{2}}[/tex]. However, the net force on the barge is normal to this direction. Therefore, the resultant force should be equal to zero.
That gives a system of two equations and two unknowns:
[tex]\displaystyle \frac{F_1 + F_2}{\sqrt{2}} = 5\; \rm kN[/tex], and[tex]\displaystyle \frac{F_1 - F_2}{\sqrt{2}} = 0[/tex].The second equation suggests that [tex]F_1 = F_2[/tex]. Hence, replace the [tex]F_2[/tex] in the first equation with [tex]F_1[/tex] and solve for [tex]F_1\![/tex]:
[tex]F_1 = \displaystyle \frac{5\; \rm kN}{2\, \sqrt{2}} \approx 3.5\; \rm kN[/tex].
Because [tex]F_1 = F_2[/tex] (as seen in the second equation,) [tex]F_2 = F_1 \approx 3.5\; \rm kN[/tex].
In other words, the tension in each of the two ropes is approximately [tex]3.5\; \rm kN[/tex].
The tension in each of the rope is 3,535.5 N
The given expression:
the resultant force, R = 5 kN = 5000 N
the angle in between the forces, α = 45
To find:
the tension in each of the ropesThe tension in each of the ropes is calculated as follows;
The tension in vertical direction
[tex]F_y = F \times sin(\alpha)\\\\F_y = 5000 \times sin(45)\\\\F_y = 5000 \times 0.7071\\\\F_y = 3,535.5 \ N[/tex]
The tension in horizontal direction;
[tex]F_x = F \times cos(\alpha)\\\\F_x = 5000 \times cos(45)\\\\F_x = 5000 \times 0.7071\\\\F_x = 3,535.5 \ N[/tex]
Thus, the tension in each of the rope is 3,535.5 N
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what is an emergent curriculum
Answer:
Emergent curriculum is an early education approach where teachers design projects unique to a child or group of kids.
Read each scenario below. Then select the answer choices that complete the sentences,
A car engine has
power than a house because a car engine does the same amount of work in
time,
Yaserin and Raj each had 10 tones of equal weight to stack next to each other on the same shelt, at the same height
and in the same arrangement. Vasarin completed the task in 2 minutes, wille Raj took 3 minutes to stack his bles,
Raj applied
power than Yaskrin because his stacking took turve to do the same amount of
Answer:
Higher
Lesser
Lesser
Longer
Explanation:
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ryanzl6659
14 hours ago
Physics
College
Read each scenario below. Then select the answer choices that complete the sentences,
A car engine has HIGHER power than a house because a car engine does the same amount of work in LESSER time,
Yaserin and Raj each had 10 tones of equal weight to stack next to each other on the same shelt, at the same height and in the same arrangement. Vasarin completed the task in 2 minutes, wille Raj took 3 minutes to stack his bles,
Raj applied LESSER power than Yaskrin because his stacking took LONGER to do the same amount of
Answer:
More
Less
Less
More
Explanation:
i got all correct
Let the force of the Moon on the Earth be F1. Let the force of the Earth pulling on the Moon be F2. Which of the following is greater?
The ___ of a wave is the reciprocal of its frequency.
Answer:
time period of the wave
Answer:
The Frequency of a wave is the reciprocal of its Period
The Period of a wave is the reciprocal of its frequency
Explanation:
A P E X
Ciara is swinging a 0.015 kg ball tied to a string around her head in a flat, horizontal circle. The radius of the circle is 0.70 m. The ball is going 7.33 m/s.
If the speed is tripled, what happens to its centripetal force?
a)The new centripetal force is 1/3 what it was
b)The new centripetal force is 9 times more
c)The new centripetal force is 1/9 what it was
d)The new centripetal force is 3 times more
Answer:
b)The new centripetal force is 9 times more
Explanation:
The formula to apply in this case is that of tension force on a spring which is equal to the centripetal force.
T= mv²/r --------i
where T is the tension on the spring
v= velocity/speed of the ball = 7.33 m/s
m= mass of the ball , 0.015 kg
r= radius of circle , 0.70 m
Use the values in the formula as;
T= {0.015 * 7.33² } / 0.70
T= 0.8059335 / 0.70
T= 1.15 N ---------i
If the speed is tripled then;
v= 21.99 m/s
T= 0.015 * 21.99² / 0.70
T= 10.36 N ------ii
Check the changes by dividing i and ii as ;
10.36 / 1.15 = 9.01
This is 9 times more hence if the speed is tripled ,the new centripetal force is 9 times more.
List four safety measures one should take when there is a cyclone warning.
Answer:
I'm gonna give you more than 4 So u can choose.
Turn off all electricity, gas and water.
Unplug all electrical appliances.
Keep your emergency kit close at hand.
If the building starts to collapse, protect yourself with mattresses, rugs.
Stay tuned to the radio for updates.
Stay inside until told it is safe to go outside.
What makes the atmosphere an important part of Earth’s system?
Answer:
water exchange carbon dioxide is taken away and oxygen is made
A small truck has a mass of 2085 kg. How much work is required to decrease the speed of the vehicle from 22.0 m/s to 13.0 m/s on a level road?
Answer:
Work required is 328387.5 Joules.
Explanation:
Given the following data;
Mass = 2085kg
Initial velocity, Vi = 13m/s
Final velocity, Vf =22m/s
To find the workdone;
We know that from the workdone theorem, the workdone by an object or a body is directly proportional to the kinetic energy possessed by the object due to its motion.
Mathematically, it is given by the equation;
W = Kf - Ki
Where;
W is the work required.
Kf is the final kinetic energy possessed by the object.
Ki is the initial kinetic energy possessed by the object.
But Kinetic energy = ½MV²
W = ½MVf² - ½MVi²
Substituting into the equation, we have;
W = ½(2085)*22² - ½(2085)*13²
Simplifying the equation, we have;
W = 1042.5 * 484 - 1042.5 * 169
W = 504570 - 176182.5
W = 328387.5J
Therefore, the work required to decrease the speed of the vehicle is 328387.5 Joules.
what is the surface pressure of Venus?
answers 93 bar
The atmosphere of Venus is the layer of gases surrounding Venus. It is composed primarily of carbon dioxide and is much denser and hotter than that of Earth. The temperature at the surface is 740 K (467 °C, 872 °F), and the pressure is 93 bar (9.3 MPa), roughly the pressure found 900 m (3,000 ft) underwater on Earth.