Which sequences of transformations applied to shape I prove that shape I is similar to shape II? a translation 12 units right and 5 units up, and then a dilation by a scale factor of 2 a reflection across the x-axis and then across the y-axis, and then a dilation by a scale factor of 2 a 180° counterclockwise rotation about the origin, and then a dilation by a scale factor of 2 a reflection across the y-axis, and then a dilation by a scale factor of 2 a reflection across the x-axis, and then a dilation by a scale factor of 2

Answer:

Highest temperature=56.7°C

Lowest temperature= -89.2°C

Difference between the temperatures = 89.2+56.7=145.9

Answer:

5

Step-by-step explanation:

Answer:

a = -10

Step-by-step explanation:

solving inequation : a [tex]\leq[/tex] -6.5    so   a = -10   complies

Answer:

a=-10

Step-by-step explanation:

[tex]2a-7\leq -20\\2a\leq -13\\a\leq -6.5\\[/tex]

The only solution that fits this is a=-10

Answer:

'no'

Step-by-step explanation:

Answer:

x^3+6x^2-6x-11

Step-by-step explanation:

PLEASE GIVE BRAINLIEST

(x² - 6) (x + 6) + 25

x²(x + 6) + -6(x + 6) + 25

x³ + 6x² - 6x - 36 + 25

x³ + 6x² - 6x - 11

Answer:

Parallel lines

Step-by-step explanation:

Answer:

24

Step-by-step explanation:

4.8×5 you have 5 candy bars that are $4.80 each so you multiply that by 5.

Answer:

2,33

Step-by-step explanation:

because if you multiply 3 + 9 you,ve got 27 besides 6

Responder: 36.9

explicación paso a paso:

1771.2 / 48 = 36.9

Answer:

$437

Step-by-step explanation:

There are 7 days in a week.

Let's stop at the last even number, the 6th day.

Tuesday is four days away from Sunday, so multiply 122 by 3.

[tex]\mathrm{122}[/tex] × [tex]3[/tex] = [tex]366[/tex]

Finally, we are at the 7th day. There is no 8th day in a week, so divide 122 by 2.

[tex]122[/tex] ÷ [tex]2[/tex] [tex]=61[/tex]

Now, let's add 61 to 366. We get $437, and that is our answer.

Hope this helps!

25% of $35 is 8.75, so the price would be $26.25. plus tax, the final price would be $27.825 or $27.83. if that doesn't work, try $27.82

(i was wrong before, this should be right now)

hope this helps!! :)

Answer:man I’m sry

Step-by-step explanation:

Answer:

Step-by-step explanation:

Determine the domain. The excluded values are those values for the variable that result in the expression having a denominator of 0.

Factor the numerator and denominator.

Find common factors for the numerator and denominator and simplify.

Answer:

Answer is B

Step-by-step explanation:

If you are unsure about where to start, you could always plot some numbers down until you see a general pattern.

But a more intuitive way is to determine what happens during each transformation.

A regular y = |x| will have its vertex at the origin, because nothing is changed for a y = |x| graph. We have a ray that is reflected at the origin about the y-axis.

Now, let's explore the different transformations for an absolute value graph by taking a y = |x + h| graph.

What happens to the graph?

Well, we have shifted the graph -h units, just like a normal trigonometric, linear, or even parabolic graph. That is, we have shifted the graph h units to its negative side (to the left).

What about the y = |x| + h graph?

Well, like a parabola, we shift it h units upwards, and if h is negative, we shift it h units downwards.

So, if you understand what each transformation does, then you would be able to identify the changes in the shape's location.

Answer:

answer is b

Step-by-step explanation:

because i got it right on E D G E

Answer:

34.5

17.1

Step-by-step explanation:

Answer:

The investment required is: $5687

Step-by-step explanation:

Future Amount A= $7000

Rate r = 6% =0.06

Time t = 4

Compounded Weekly = n= 52

We need to find Principal Amount P

The formula used is: [tex]A=P(1+\frac{r}{n})^{n*t}[/tex]

Putting values and finding P

[tex]A=P(1+\frac{r}{n})^{n*t}\\7000=P(1+\frac{0.06}{52})^{4*52}\\7000=P(1.001)^{208}\\7000=P(1.231)\\P=\frac{7000}{1.231} \\P=5687[/tex]

So, The investment required is: $5687

Answer:

1o

2true I helped it help

Answer:

9

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Step-by-step explanation:

Step 1: Define expression

8 - 2 · 3 + 7

Step 2: Evaluate

Answer:

30 builders

Step-by-step explanation:

80÷5=16

6x5=30

Answer:

true

Step-by-step explanation:

Answer:

true is the answer yyyt

Answer:

Miling saves more because he saves 15 dollars a week while Daniel saves 10 dollars a week 10 dollars is less than 15 dollars

9514 1404 393

Answer:

  y > 0

Step-by-step explanation:

The range of the function ...

  y = e^(4x)

is the same as the range of any exponential function:

  y > 0

The function can take on any positive value, but will never be 0 or negative. It has a horizontal asymptote of y=0.

The range of the given function is y > 0.

A function is a relation from a set A to a set B where the elements in set A only maps to one and only one image in set B. No elements in set A has more than one image in set B.

Given function is,

y = e⁴ˣ

This is an exponential function.

The range of any exponential function is all the real numbers which are greater than 0.

So here also, the range is all the real numbers which are greater than 0.

So range is y > 0.

Hence the correct option is B.

Learn more about Exponential Functions here :

https://brainly.com/question/28596571

#SPJ7

Answer:

9×−6

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Thats the answer put that Promise can I get brainliest just click on my profile then go back and youĺl see a crown and click it on my name

Step-by-step explanation:

Answer:

The solutions are x=4,x=−10. Explanation: The square root property involves taking the square root of both the terms on either side of the ...

1 answer

Step-by-step explanation:

Answer:

[tex]\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}[/tex]

[tex]x=\frac{3+\sqrt{29}}{2},\:x=\frac{3-\sqrt{29}}{2}[/tex]

Step-by-step explanation:

Given the equation

[tex]x^2\:-3x\:-\:5\:=\:0[/tex]

solving with the quadratic formula

[tex]\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}[/tex]

[tex]x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}[/tex]

[tex]\mathrm{For\:}\quad a=1,\:b=-3,\:c=-5[/tex]

[tex]x_{1,\:2}=\frac{-\left(-3\right)\pm \sqrt{\left(-3\right)^2-4\cdot \:1\cdot \left(-5\right)}}{2\cdot \:1}[/tex]

[tex]x_{1,\:2}=\frac{-\left(-3\right)\pm \sqrt{29}}{2\cdot \:1}[/tex]

separating the solutions

[tex]x_1=\frac{-\left(-3\right)+\sqrt{29}}{2\cdot \:1},\:x_2=\frac{-\left(-3\right)-\sqrt{29}}{2\cdot \:1}[/tex]

solving

[tex]x=\frac{-\left(-3\right)+\sqrt{29}}{2\cdot \:\:1}[/tex]

  [tex]=\frac{3+\sqrt{29}}{2\cdot \:1}[/tex]

  [tex]=\frac{3+\sqrt{29}}{2}[/tex]

also solving

[tex]\:x=\frac{-\left(-3\right)-\sqrt{29}}{2\cdot \:\:1}[/tex]

  [tex]=\frac{3-\sqrt{29}}{2\cdot \:1}[/tex]

  [tex]=\frac{3-\sqrt{29}}{2}[/tex]

[tex]\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}[/tex]

[tex]x=\frac{3+\sqrt{29}}{2},\:x=\frac{3-\sqrt{29}}{2}[/tex]