While sitting on a park bench, Tanisha counts that 16 out of 20 people who walk by her have a pet with them.

Part A. What is the probability that a person who walks by Tanisha has a pet?

Part B. What is the probability that a person who walks by her does not have a pet?

Answer:

the answer would be-

Step-by-step explanation:

The probability that a person who walks by Tanisha has a pet- 0.8

The probability that a person who walks by Tanisha does not have a pet- 0.2

Probability is a mathematical term, which can be defined as the ratio of the number of favorable outcomes to the total number of outcomes of an event.

Probability of Event = Favorable Outcomes/Total Outcomes = X/n

Part A. The probability that a person who walks by Tanisha has a pet can be calculated by dividing the number of people who have a pet by the total number of people who walk by her. In this case, 16 out of 20 people have a pet, so the probability is:

P(having a pet) = 16/20 = 4/5 = 0.8

So, the probability that a person who walks by Tanisha has a pet is 0.8 or 80%.

Part B. The probability that a person who walks by Tanisha does not have a pet can be calculated by subtracting the probability of having a pet from 1. That is:

P(not having a pet) = 1 - P(having a pet)

P(not having a pet) = 1 - 0.8

P(not having a pet) = 0.2

So, the probability that a person who walks by Tanisha does not have a pet is 0.2 or 20%.

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