Workers load 5 identical large crates and 3 identical small crates onto a freight elevator. The crates have a combined weight of 1375 pounds. Later
that day, the workers load 3 more identical large crates and 6 more identical small crates onto the freight elevator. These crates have a combined
weight of 1350 pounds.

Answer

40.9

Step-by-step explanation:

Answer:

40.9 mm

Step-by-step explanation:

116.9 - (35.1 + 40.9) = 116.9 - 76 = 40.9 mm

Answer:

the blue one

Step-by-step explanation:

Answer:

B and C

if n=3 then 5ⁿ=5³=5×5×5=125

n³=3³=3×3×3=27

hope it helps :)

Answer:

yes It has

Step-by-step explanation:

v of the tank

v= [tex]\pi[/tex]r^2  h

v=3.14*144*20

v=9034

the v of each ballon :

V = 4/3 [tex]\pi[/tex]r^3

v=4/3 * 3.14 .8

v= 33.5

all the ballons v is 250 * 33.5 = 8373

9034-8373 = 661 v of the water in the tank would be left

Answer: 3.25 miles

Step-by-step explanation:

6 + 7 = 13

13 x .25 = 3.25

Complete question :

Stephanie has six identical gift boxes to wrap. Each box is a cube that measures 6 inches on each side. She would like to wrap them all using the same gift wrapping paper. The roll of wrapping paper she has is 30 inches wide and 10 feet long.

Answer:

Left over = 2292 in²

Step-by-step explanation:

Given that :

Gift boxes are identical ;

Each gift box is a cube with side length, s = 6 inches

Area of gift box, Surface area of a cube = 6s²

Area = 6(6²) = 6 * 36 = 216 in²

Area of one gift box = 216 in²

6 gift boxes will be : 216 in² * 6 = 1296 in²

Allowing 2 inches to cover for overlap in each box : 2 inches * 6 = 12 in²

Dimension of wrapping paper = 30 inches by 10 feets

Recall :

1 Feet = 12 inches

Hence ; dimension of wrapping paper becomes :

30 inches by (10*12) inches

30 inches by 120 inches

Area of wrapping paper = 30 * 120 = 3600 in²

Total area of paper - area of gifbox - area of overlap

(3600 - 1296 - 12) in²

= 2292 in²

Leftover = 2292 in²

Answer:

A. x^2+3x-4

B. 6x^2-5x+1

Answer:

A: x^2+3x-4

B: 6x^2 -5x +1

Step-by-step explanation:

Alright, so for this, use the FOIL method, by multiplying the terms of each question in this order:

First

Outer

Inner

Last

So with the first question, lets do this:

(x+4)(x-1)

F: x * x = x^2

O: x * -1 = -x

I: x * 4 = 4x

L: 4 * -1 = -4

Then combine the like terms together:

x^2 + -x + 4x -4

A: x^2+3x-4

With the next one, same deal:

(2x-1)(3x-1)

F: 2x * 3x = 6x^2

O: 2x * -1 = -2x

I: 3x * -1 = -3x

L: -1 * -1 = 1

Then combine them up:

6x^2 -2x -3x +1

B: 6x^2 -5x +1

All done!

Answer:

280

Step-by-step explanation:

Answer: second one

Step-by-step explanation:

Answer:

3282 m^2

Step-by-step explanation:

volume of a hemisphere = (2/3) x (n) x (r^3)

n = 22/7

r = radius

r = (450,000 x (3/2) x(1/3.14)) ^1/3

r = 45.72

Area of a semicircle = 1/2 x n x r^2

1/2 x 45.72^2 x 3.14 = 3282 m^2

Answer:

The object is moving at a constant speed

Step-by-step explanation:

Answer:

?

Step-by-step explanation:

Answer:

ill help but i need the question

Answer:

I'm not totally sure, but I think the answer is thousands.

Step-by-step explanation:

Answer:

The mean is 4

Step-by-step explanation:MRK ME BRAINLIEST PLZZZZZZZZZZZZZz

ita 4 because first you add up the 10,3,2,5,0. and then it equals 20 and then divided and get the mean which is 4

Answer:

4 points

Step-by-step explanation:

is the answer

Answer:

3)

Each stripe is 1/18 yards thick, and the fence post if 5/6 yards. Therefore, we have to find how many 1/18s can go into 5/6. Thus, this is a matter of division, and we do 5/6 divided by 1/18 to find how many stripes we can have.

5/6 ÷ 1/18 = 5/6 * 18 = 15

Thus, the answer is D.

4) A is 3, which means we substitute all the "a"s in the expression for 3. Thus we have:

99 - 7[tex]a^{2}[/tex]

99 - 7(3)^2

99 - 7(9)

99 - 63 = 36

Therefore, it is 36.

Answer:

I can't find that file. please give it again.

Answer:

hola la respuesta es 3900 y 2348

Step-by-step explanation:

espero que te sirva

The true statements concerning trapezoid RSTU are:

STUT

CABRS

DRS UT

Based on the given information that Trapezoid ABCD has been translated down and to the right to form trapezoid RSTU, we can determine the relationships between the corresponding sides and angles of the two trapezoids.

Given:

AB || DC

Based on the parallel lines, we can infer the following relationships:

Corresponding sides are parallel:

RS || UT (corresponds to AB || DC)

ST || RU (corresponds to BC || DA)

Corresponding angles are congruent:

∠R ≅ ∠A

∠S ≅ ∠B

∠T ≅ ∠C

∠U ≅ ∠D

From these relationships, we can determine the following statements that are true concerning trapezoid RSTU:

STUT (corresponds to ABCD): The bases of the trapezoids are parallel, so the order of the vertices remains the same.

CABRS (corresponds to DCBA): The corresponding angles in trapezoid RSTU and trapezoid ABCD are congruent.

DRS UT (corresponds to ABDC): The order of the vertices is reversed, but the parallel sides and corresponding angles remain the same.

Therefore, the true statements concerning trapezoid RSTU are:

STUT

CABRS

DRS UT

To know more about trapezoid here

https://brainly.com/question/1410008

#SPJ2

Answer:

The area of the cube is equal to [tex]0.375\ \text{foot}^2[/tex].

Step-by-step explanation:

The formula for the surface area of a cube is :

[tex]A=6s^2[/tex]

Where

s is the cube's side length

Put s = 1/4 foot

So,

[tex]A=6\times (\dfrac{1}{4})^2\\A=0.375\ \text{foot}^2[/tex]

So, the area of the cube is equal to [tex]0.375\ \text{foot}^2[/tex].

Answer:

2 ft

Step-by-step explanation:

Perimeter = 4 * sides

8 ft = 4 * s

side = 2 ft

Answer:

2 ft

Step-by-step explanation:

8/4 = 2

Answer:

A. 6cm, 7cm, 8cm represents the lengths of a given right angle

Answer:

Whats the question?

Step-by-step explanation:

Answer-

5/6

Step-by-step explanation:

Answer:

a-

Step-by-step explanation:

hi

Answer:

9 sq. units

Step-by-step explanation:

dimensions of rectangle are (7-3),(8-3)

or 4,5

area of rectangle=4×5=20

area of bottom Δ=1/2×4×2=4

area of top Δ=1/2×3×3=9/2

area of right triangle=1/2 ×5×1=5/2

area of Δ HIJ=20-(4+9/2+5/2)

=20-(4+14/2)

=20-(4+7)

=9 sq. units.

or area of triangle =1/2

| 3  5 |

| 7  3 |

|6   8 |

|3   5 |

=1/2[(9-35)+(56-18)+(30-24)]

=1/2[-26+38+6]

=1/2[-26+44]

=1/2(18)

=9 sq. units.

Respuesta:

Perímetro de la parte sombreada = (6pi + 24)

Explicación paso a paso:

Encuentra el diagrama adjunto

Primero necesitamos encontrar el perímetro de los semicírculos externos que sobresalen

Diámetro del semicírculo = 1/2 de la longitud del lado del cuadrado

Diámetro del semicírculo = 1/2 × 6 m = 3 m

Perímetro de los 4 semicírculos = 4 (pi d)

Perímetro de los 4 semicírculos = 4 × 3,14 × 3

Perímetro de los 4 semicírculos exteriores = 1

2pi cm

Para la parte interior sombreada = Perímetro de todo el cuadrado - Perímetro de semicírculo (2 cuadrantes)

Perímetro del cuadrado entero = 4 (6) = 24m

Perímetro de los 2 cuadrantes = pi d

Perímetro de los 2 cuadrantes = 6pi cm

Para la parte sombreada interior, perímetro = 24-6pi

Perímetro de la parte sombreada = 12pi + 24-6pi

Perímetro de la parte sombreada = (6pi + 24) cm