Write and solve an equation for the following.

Four more than one-half a number is three. What is the number?

Answer:

top and bottom

Step-by-step explanation:

Answer:

54ft

Step-by-step explanation:

9ft x 6ft

Answer:

LDM

MDL

Step-by-step explanation:

The names of a figure are gotten from the points on the figure. The names of the figure are LDM  and MDL.

There are three points on the given figure, and these points are: point L, point D and point M, where Point D is between L and M.

This means that, when naming the figure, alphabet D must be at the middle while alphabets M and L can be at either sides of D.

So, the possible names of the figure are: LDM  and MDL.

Read more about naming figures at:

https://brainly.com/question/1514423

Answer:

volume =

[tex] {7}^{2} \times 3.14 \times 2 \times 4[/tex]

Step-by-step explanation:

volume =area of the base circle × height

Answer:

27

Step-by-step explanation:

30/100 ×90 is 27.

it's making me type more but that's the answer :)

Answer:

30%×90

=30/100×90

=27 is the answer of this question

Answer:

The average function [tex]f_{avg}[/tex] value = 4

Step-by-step explanation:

Given that:

[tex]f(x,y,z) = 3x^2z+3y^2z[/tex]

The enclosed region [tex]z = 4 -x^2 -y^2[/tex] and the plane z = 0.

Over an area E, the average value of a function f(x,y,z) is:

[tex]f_{avg} = \dfrac{1}{V_{E}} \iiint_E f(x,y,z) dV ------ (1)[/tex]

where;

[tex]V_E[/tex] = volume of region E

To find the volume use cylindrical coordinates;

[tex]x=rcos \theta; \ \ \ y = rsin \theta; \ \ \ z = z[/tex]

Then;

E = 0 ≤ r ≤2, 0 ≤ θ ≤ 2π, 0 ≤ z ≤ 4 - r²

[tex]V_E = \int^{2 \pi}_{0} \int^{2}_{0} \int^{4-r^2}_{0} \ rdzdrd \theta[/tex]

[tex]V_E = \int^{2 \pi}_{0} \int^{2}_{0} r(4-r^2) \ drd \theta[/tex]

[tex]V_E = \int^{2 \pi}_{0} \int^{2}_{0} (4r-r^3) \ drd \theta[/tex]

[tex]V_E = \int^{2 \pi}_{0} \Big(2r^2- \dfrac{r^4}{4} \Big)^2_0 \ d \theta[/tex]

[tex]V_E = 4(2 \pi)\\\\ V_E = 8 \pi[/tex]

However, from equation (1):

[tex]f_{avg} = \dfrac{1}{V_E} \iiint_E f(x,y,z) \ dV \\ \\ = \dfrac{1}{8 \pi} \iiint_E (3x^2z + 3y^2 z) dV \\ \\ = \dfrac{1}{8 \pi } \int^{2 \pi}_{0} \int^{2 }_{0} \int^{4 - r^2}_{0} \ \ 3zr^2 \ rdzdrd\theta \\ \\ = \dfrac{3}{8 \pi} \int^{2 \pi}_{0} \int^{2 }_{0} \Big(\dfrac{z^2}{2}\Big)^{4-r^2}_{0} \ r^3 drd\theta \\ \\ = \dfrac{3}{16 \pi} \int^{2 \pi}_{0} \int^{2 }_{0} (4-r^2)^2 \ r^3 \ dr d\theta[/tex]

[tex]= \dfrac{3}{16 \pi} \int^{2 \pi}_{0} \int^{2 }_{0} (16-8r^2 + r^4)r^3 \ dr d\theta \\ \\ = \dfrac{3}{16 \pi} \int^{2 \pi}_{0} \int^{2 }_{0} (16r^3 -8r^5 + r^7) \ dr d \theta \\ \\ = = \dfrac{3}{16 \pi} \int^{2 \pi}_{0} \Big (4r^4 - \dfrac{8}{6}r^6 + \dfrac{r^8}{8} \Big)^2_0 \ d \theta \\ \\ = \dfrac{3}{16 \pi } (2 \pi) \Big (64 - \dfrac{8}{6} \times 64 \times \dfrac{256}{8} \Big) \\ \\ = \dfrac{3}{16 \pi} (2 \pi) (\dfrac{32}{3}) \\ \\ = 4[/tex]

Answer:

....

Step-by-step explanation:

mean: 16

median: 16

there is no mode

range: 8

Answer:

[tex]3\frac{7}{8}[/tex]

Step-by-step explanation:

Equation: 4 1/7 + 2 1/8 + x= 10 1/7

Convert into improper fractions:

29/7 + 17/8= 71/7

Add fractions

351/56+x= 71/7

Subtract on both sides

X= 31/8 or 3 7/8

Answer:

Alright but first

How is this 7th grade stuff?

I thoguh yall were doing algebra. But it kinda looks like it but here’s a brief explanation anyway.

If you dont know a vualure, use other surrounding it to help you sovle this final thingy. Like if its division, multiply. addditon, subtract. multiply, Davison. Just tdo inver properties on both sides and isolate the number that x in it Either be dividing or multiplying. When your left with a final value just solve, whatever thing that lies next to that equal sign is your answer.

2) 6

3) -36

4) 40

5) 9

6) -4

7) 63

8) -48

9) -5

10) -7

Answer:

C

Step-by-step explanation:

6 * 5 = 30

3*4 = 12

30 + 12 = 42

42 does not equal 18

Answer:

The answer is C. (5,4)

Step-by-step explanation:

have a great day.

Answers:

d = v(initial)t + 1/2(at^2)

v(final) = √(v(initial)^2 + 2ad)

a = 2(d-v(initial)t) / t^2

t = -v(initial)±√(v(initial)^2 + 2ad) / a

Answer:

1. vt-d=1/2at^2

2. d-vt=1/2at^2

3. a=2(d-vt)/t^2

Step-by-step explanation:

[tex]6^{2}+8^{2}=x^{2} \\36+64=x^{2} \\100=x^{2} \\x=10[/tex]

Answer:

The wingspan of a pelican is 1 8/15 feet longer than the wingspan of an eagle.

(1 whole 8/15 feet)

Step-by-step explanation:

We'll need to find a common denominator for the fractions. 15 is the lowest number divisible by both 5 and 3, so we'll use 15. For this problem, it's also easier to convert to improper fractions, in my opinion.

Pelican:

8 1/5 = 41/5

41/5 x 3/3 = 123/15

Eagle:

6 2/3 = 20/3

(20/3) x (5/5) = 100/15

Find the difference:

123/15 - 100/15 = 23/15 = 1 8/15

Please let me know if you have questions.

Ewan HH

Step-by-step explanation:

Ewanjajsbehudbeiisiejebejehehehheehhehehe

Answer:

???

Step-by-step explanation:

Answer:

119

Step-by-step explanation:

A=w 1=7x17=119

Answer:

37.699 cubic inches of water

Step-by-step explanation:

Volume of a cone is V= 1/3 pi r^2 h

We are given that the height is 5 in and the radius is 2 in.

Plug that into the formula: V= 1/3 pi 2^2 9

1/3 x 4 x 9 = 12

Now we are left with 12 pi.

Use a calculator and multiply 12 by pi to get:

37.699

Answer:

3x+5-7

Step-by-step explanation:

Answer:

If im not mistaken it should be answer 3. Because you would have to divide amongst groups.

Answer:

She can cut 6 nine inch pieces.

Step-by-step explanation:

12x5=60 and 9 goes into 60 6 times which equals 54.

Step-by-step explanation:

i can't help you because that i am no a unit test i am so sorry for not help you

Answer: AA

Step-by-step explanation:

You can do vertical angles or alternate interior angles. Hope this helps :)

Answer:

hope this helps :D

Step-by-step explanation:

Perfect cube factors:

If a number is a perfect cube, then the power of the prime factors should be divisible by 3.

Example 1:Find the number of factors of293655118 that are perfect cube?

Solution: If a number is a perfect cube, then the power of the prime factors should be divisible by 3. Hence perfect cube factors must have

2(0 or 3 or 6or 9)—– 4 factors

3(0 or 3 or 6)  —–  3  factors

5(0 or 3)——- 2 factors

11(0 or 3 or 6 )— 3 factors

Hence, the total number of factors which are perfect cube 4x3x2x3=72

Perfect square and perfect cube

If a number is both perfect square and perfect cube then the powers of prime factors must be divisible by 6.

Example 2: How many factors of 293655118 are both perfect square and perfect cube?

Solution: If a number is both perfect square and perfect cube then the powers of prime factors must be divisible by 6.Hence both perfect square and perfect cube must have

2(0 or 6)—– 2 factors

3(0 or 6) —– 2 factors

5(0)——- 1 factor

11(0 or 6)— 2 factors

Hence total number of such factors are 2x2x1x2=8

Example 3: How many factors of293655118are either perfect squares or perfect cubes but not both?

Solution:

Let A denotes set of numbers, which are perfect squares.

If a number is a perfect square, then the power of the prime factors should be divisible by 2. Hence perfect square factors must have

2(0 or 2 or 4 or 6 or 8)—– 5 factors

3(0 or 2 or 4 or 6)  —– 4 factors

5(0 or 2or 4 )——- 3 factors

11(0 or 2or 4 or6 or 8 )— 5 factors

Hence, the total number of factors which are perfect square i.e. n(A)=5x4x3x5=300

Let B denotes set of numbers, which are perfect cubes

If a number is a perfect cube, then the power of the prime factors should be divisible by 3. Hence perfect cube factors must have

2(0 or 3 or 6or 9)—– 4 factors

3(0 or 3 or 6)  —–  3  factors

5(0 or 3)——- 2 factors

11(0 or 3 or 6 )— 3 factors

Hence, the total number of factors which are perfect cube i.e. n(B)=4x3x2x3=72

If a number is both perfect square and perfect cube then the powers of prime factors must be divisible by 6.Hence both perfect square and perfect cube must have

2(0 or 6)—– 2 factors

3(0 or 6) —– 2 factors

5(0)——- 1 factor

11(0 or 6)— 2 factors

Hence total number of such factors are i.e.n(A∩B)=2x2x1x2=8

We are asked to calculate which are either perfect square or perfect cubes i.e.

n(A U B )= n(A) + n(B) – n(A∩B)

=300+72 – 8

=364

Hence required number of factors is 364.

Answer:

Cylinder

Step-by-step explanation:

A cone is a 3D triangle with a circular base, and a sphere is a 3D circle

Answer:

CYLIDER

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

No its not

Step-by-step explanation:

13.603 is more then 13.068  

Answer:

I think this would be,

ADE = 180- BCE

I am not sure if this is the right answer, and i am sorry if the answer is wrong, i am just learning about this topic.

Answer:

m<ADC= 180-m<ABC or m<ABC=180-m<ADC

Step-by-step explanation:

Firstly, we need to establish that trapezoid ABCD is an isosceles trapezoid. By doing so, we know that angles opposite one another in an isoseles trapezoid are supplementary. As a result, m<ACD+m<ABC= 180. We can now solve for angle ACD or ABC.

Answer:

a) P(X < 99) = 0.2033.

b) P(98 < X < 100) = 0.4525

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 100 and variance of 36.

This means that [tex]\mu = 100, \sigma = \sqrt{36} = 6[/tex]

Sample of 25:

This means that [tex]n = 25, s = \frac{6}{\sqrt{25}} = 1.2[/tex]

(a) P(X<99)

This is the pvalue of Z when X = 99. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{99 - 100}{1.2}[/tex]

[tex]Z = -0.83[/tex]

[tex]Z = -0.83[/tex] has a pvalue of 0.2033. So

P(X < 99) = 0.2033.

b) P(98 < X < 100)

This is the pvalue of Z when X = 100 subtracted by the pvalue of Z when X = 98. So

X = 100

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{100 - 100}{1.2}[/tex]

[tex]Z = 0[/tex]

[tex]Z = 0[/tex] has a pvalue of 0.5

X = 98

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{98 - 100}{1.2}[/tex]

[tex]Z = -1.67[/tex]

[tex]Z = -1.67[/tex] has a pvalue of 0.0475

0.5 - 0.0475 = 0.4525

So

P(98 < X < 100) = 0.4525