Answer:
False
Explanation:
The answer is False that, additional information about a test in a one-on-one meeting would not be fair to the other students.
What is the meeting like?A meeting is a Group of two or more individuals who have been asked to get together too to speak verbally and work toward a similar objective, such as exchanging information or coming to a result. A meeting, according to one Merriam-Webster dictionary, is an act or process of getting together, such as a gathering for a shared cause.
Any event scheduled at a hotel, convention hall, or other location specifically designed for such gatherings may be referred to as a "meeting" by planners and other meet-and-greet specialists.
Meetings can include lectures (one presentation), seminars (typically several lectures, a comparatively tiny audience, one day), conferences (mid-size, each or more days), congresses (large, several days), exhibitions or trade shows (with manned stands being visited by passersby), workshops, trainings, team-building activities, and kick-off events.
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If an area has limited types of wildlife, this means that it has __________. A. animals that are about to go extinct B. animals that have adapted well to their environments C. a wide variety of animals D. very few varieties of animals Please select the best answer from the choices provided A B C D
Answer:
It is d
Explanation:
Answer:
D !!!!!
Explanation:
A skydiver, with a mass of 60 kg is falling at a velocity of 30 m/s. Calculate his kinetic energy.
Answer:
27000 J
Explanation:
If Juan upgrades from a sports car to a large truck, what will happen to the
force needed to keep the truck going at the same speed? Use this
sentence frame:
Answer:
The force must increase
Explanation:
According to newton's second law "force is the product of mass and acceleration".
Force = mass x acceleration
Now, the mass of the sports car is lesser compared to that of the truck. Therefore, to take both automobiles to the same speed, enough force must be applied by the engine of the truck.
There must be an increase in the force in order to make both automobiles attain the same speed.
The force F⃗ pulling the string is constant; therefore the magnitude of the angular acceleration α of the wheel is constant for this configuration. Find the magnitude of the angular velocity ω of the wheel when the string has been pulled a distance d. Note that there are two ways to find an expression for ω; these expressions look very different but are equivalent.
Answer:
The answer is "[tex]\boxed{\boxed{\omega = \sqrt{\frac{2fd}{kmr^2}}}}[/tex]"
Explanation:
[tex]\to d= r \theta \\\\ \to \theta =\frac{d}{r}\\\\\to \omega^{r} - \omega_{0}^{r} = 2 \alpha \theta\\\\\to \omega^{r} = 2 \alpha \theta - \omega_{0}^{r} \\\\\to \omega^{r} = 2 (\frac{F}{Kmr}) \frac{d}{r}\\\\\to \omega = \sqrt{\frac{2fd}{kmr^2}}[/tex]
The angular velocity of the wheel is [tex]\omega=\sqrt{\frac{Fd}{mkr^2} }[/tex]
Angular Velocity :Given that the force applied is F, and the displacement of the string is d.
If the radius of the wheel is r and the wheel has an angular displacement of θ, then:
d = rθ
θ = d/r
now, the angular acceleration is given by:
α = F/mkr
The initial angular velocity will be zero and let the final angular velocity is ω.
According to the third equation of motion:
ω² = 0 + 2αθ
ω² = 2(F/mkr)(d/r)
[tex]\omega=\sqrt{\frac{Fd}{mkr^2} }[/tex]
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What is the angular displacement (in radians) of a person standing at the Earth's equator for 6 hours assuming the Earth has a diameter of 13750 km
Answer:
π/2 radians.
Explanation:
Angular Displacement
It's the angle expressed in radians, degrees, revolutions, etc. through which a point revolves around a point called the center.
To find the angular displacement, we must recall a full revolution, or turn around the center measures 360 degrees, or 2π radians.
The Earth completes a turn every 24 hours. This means that in 6 hours, it has given 6/24 = 1/4 of a turn.
This means that, measured in radians, the angular displacement of a person during 6 hours is:
1/4*2π radians
Simplifying:
π/2 radians.
A block slides down an incline of angle 30° with an
g
acceleration of where 'g' is acceleration due to gravity.
4
Find the coefficient of kinetic friction.
7. Complete the following table, comparing forces within atoms.
Electromagnetic force
Strong Nuclear Force
Weak force
Gravity
Electromagnetic powers versus Molecules:
Electrons are kept in the circle around the core by the electromagnetic power, in light of the fact that the core in the focal point of the particle is decidedly charged and pulls in the contrarily charged electrons.
Solid Nuclear power versus Molecules:
The solid atomic power holds most standard issue together on the grounds that it limits quarks into hadron particles, for example, the proton and neutron.
Feeble power versus Molecules:
In atomic material science and molecule physical science, the frail cooperation, which is additionally frequently called the powerless power or feeble atomic power, is the instrument of communication between subatomic particles that is liable for the radioactive rot of iotas.
Gravity Vs. Particles:
Gravity influences molecules a similar way it influences all other issue. Each iota makes its own gravitational field which draws in all other issue known to man.
If 1 kg = 2.2046 Ib, how many pounds equal 5.0 kilograms?
A car moving at a speed of 20m/s has a kinetic energy of 300,000 J what’s the cars mass
Answer:
1500 kgExplanation:
The mass of the car can be found by using the formula
[tex]m = \frac{2k}{ {v}^{2} } \\ [/tex]
From the question we have
[tex]m = \frac{2 \times 300000}{ {20}^{2} } = \frac{600000}{400} = \frac{6000}{4} \\ [/tex]
We have the final answer as
1500 kgHope this helps you
How long does it take for light to travel 1m? and a 1mm?
Answer:
Hi. U should do like this
Answer:
3.335641 nanoseconds for meters
Which part of the electromagnetic spectrum has a lower frequency than visible light? x-rays ultraviolet infrared gamma rays
The answer is infrared.
Two loudspeakers emit sound waves of the same frequency along the x-axis. The amplitude of each wave is a. The sound intensity is minimum when speaker 2 is 10 cm behind speaker 1. The intensity increases as speaker 2 is moved forward and first reaches maximum, with amplitude 2a, when it is 30 cm in front of speaker 1. What is What isThe amplitude of the sound (as a multiple of a) if the speakers are placed side by side?
Answer:
Explanation:
To find the amplitude of the sound, we must first determine the wavelength and the phase difference between the two speakers.
For the wavelength;
Recall that, the separation between two successive max. and min. intensity points are [tex]\dfrac{\lambda}{2}[/tex]
Thus; for both speakers; the wavelength of the sound is:
[tex]\dfrac{\lambda}{2} = (10+30) cm[/tex]
[tex]\dfrac{\lambda}{2} = (40) cm[/tex]
λ = 80 cm
The relation between the path difference(Δx) and the phase difference(Δ∅) is:
[tex]\Delta \phi = \dfrac{2 \pi}{\lambda}\Delta x + \Delta \phi_o[/tex]
where;
Δx = 10 cm
λ = 80 cm
Δ∅ = π rad
∴
[tex]\Delta \phi = \dfrac{2 \pi}{\lambda}\Delta x + \Delta \phi_o[/tex]
[tex]\pi \ rad = \dfrac{2 \pi}{80 \ cm}(10 \ cm) + \Delta \phi_o[/tex]
[tex]\pi \ rad = \dfrac{2 \pi}{8}+ \Delta \phi_o[/tex]
[tex]\pi \ rad = \dfrac{ \pi}{4}+ \Delta \phi_o[/tex]
[tex]\Delta \phi_o = \pi -\dfrac{ \pi}{4}[/tex]
[tex]\Delta \phi_o = \dfrac{ 4\pi - \pi}{4}[/tex]
[tex]\Delta \phi_o = \dfrac{ 3\pi}{4} \ rad[/tex]
Suppose both speakers are placed side-by-side, then the path difference between the two speakers is: Δx = 0 cm
Thus, we have:
[tex]\Delta \phi = \dfrac{2 \pi}{\lambda}\Delta x + \Delta \phi_o[/tex]
[tex]\Delta \phi = \dfrac{2 \pi}{\lambda}(0 \ cm ) + \dfrac{3 \pi}{4} \ rad[/tex]
[tex]\Delta \phi = \dfrac{3 \pi}{4} \ rad[/tex]
∴
The amplitude of the sound wave if the two speakers are placed side-by-side is:
[tex]A = 2a \ cos \bigg (\dfrac{\Delta \phi }{2} \bigg)[/tex]
[tex]A = 2a \ cos \bigg (\dfrac{\dfrac{3 \pi}{4} }{2} \bigg)[/tex]
[tex]A = 2a \ cos \bigg ({\dfrac{3 \pi}{8} } \bigg)[/tex]
A = 0.765a
The expressions for sound interference allows to find the amplitude for the wave when the two speakers are together is:
The amplitud is: A = 0.765a
Given parameters
Minimum interference speaker 2 behind speaker 1 is: Δr₁ = 10 cm Maximum interference haughty 2 in front of speaker 1 Δr₂ = 30 cmTo find
The amplitude if the speakers are side by side.
The interference phenomenon occurs when two coherent waves have paths of different lengths to reach a point, we have two extreme cases:
Constructive. When the waves arrive in phase, the expression is:Δr = [tex]2n \ \frac{\lambda}{2}[/tex]
Destructive. When the waves arrive with a phase difference of 180º, the expression isΔr = [tex](2n+1) \ \frac{\lambda}{2}[/tex]
Where Δr₁ and Δr₂ are the path difference, λ is the wavelength and n is an integer.
Let's start by looking for the wavelength that the speakers emit, see attached.
Destructive Interference Δr₂ = (2n + 1) la / 2
Constructive interference Δr₁ = 2n lam / s
Let's solve the system.
Δr₂ - Δr₁ = [tex]\frac{\lambda}{2}[/tex]
Let's calculate
30 - (-10) = [tex]\frac{\lambda}{2}[/tex]
λ = 80 cm
Now we can use the general relation for the path change and the phase.
[tex]\frac{\delta r}{\lambda } = \frac{\phi - \phi_o}{2\pi }[/tex]
[tex]\phi = \frac{\Delta r \ 2\pi }{\lambda } + \phi_o[/tex]fi = Dr 2pi / lam + fio
Where [tex]\phi[/tex] is the possible initial phase difference between the speakers.
Let's find the initial phase difference emitted by the two speakers, let's use destructive interference, for which the phase difference is:
[tex]\phi = \pi \ rad[/tex]
Let's calculate
[tex]\pi = \frac{2\pi }{80} \ 10 + \phi_o \\\phi_o = \pi - \frac{\pi}{4}[/tex]
[tex]\phi_o[/tex] = ¾ [tex]\pi[/tex] rad
This value is kept constant, let's find the phase angle for when the speakers are together, so the path difference is zero Δr = 0
[tex]0= \frac{\phi - \phi_o}{2\pi }\\\phi = \phi_o[/tex]
[tex]\phi[/tex] = ¾ pi
The amplitude of the sound wave is
A = 2a cos [tex]\frac{\phi}{2}[/tex]
A = 2a cos ⅜ π
A = 0.765 a
In conclusion using the expression for sound interference we can find the amplitude for the wave when the two speakers are together is:
A = 0.765a
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How much work does a 25-newton force do to lift a potted plant from the floor to a shelf 1.5 meters high?
Answer:
37.5 N*m
Explanation:
w=fd
w=?
f=25 N
d=1.5 m
w=25N*1.5m=37.5 N*m
Find the force of gravity between a cubic meter of water (1000kg) and the Sun. The Sun's mass is 1.99 x10^30 kg and is 1.50 x10^11 m away.
A) 17.0 N
B) 5.90 N
C) 2.0 N
D) 47.20 N
Answer:
F = 5.9 N
Explanation:
Given that,
Mass of water, m₁ = 1000 kg
Mass of the Sun, [tex]m_2=1.99\times 10^{30}\ kg[/tex]
Distance between two bodies, [tex]r=1.5\times 10^{11}\ m[/tex]
We need to find the force of gravity between water and the Sun. The formula for the gravitational force between two bodies is given by :
[tex]F=G\dfrac{m_1m_2}{r^2}\\\\F=6.67\times 10^{-11}\times \dfrac{1000\times 1.99\times 10^{30}}{(1.5\times 10^{11})^2}\\\\F=5.89\ N[/tex]
or
F = 5.9 N
Hence, the correct option is (b).
Can someone please check my answer
Answer:The answer is circular orbits I hope this helps
Explanation:
n the diagram, the arrow shows the movement of electric charges through a wire connected to a battery.
A battery with an arrow at its top running from left to right. A black line connects the right end of the battery to the left end by making a series of straight lines to form a rectangular box with the battery as part of the bottom side.
What causes the electric charges to flow from one end of the battery to the other?
a balance in electric potential
a balance in resistance
a difference in electric potential
a difference in resistance
Answer:
D. A difference in resistance
When liquid water gets into cracks of rock and freezes, it _____ and ______.
A contracts, splits apart the rock
B contracts, washes aways pieces of rock
C expands, splits apart the rock
D expands, washes away pieces of rock
Answer: it eventually cracks the rock and breaks pieces of the rock off
Explanation:
A 10-kg wagon is pulled by a force of 70 Newtons while friction provides 20 Newtons of force. How much acceleration will the wagon have?
Answer:
5m/s²
Explanation:
Given parameters:
Mass of wagon = 10kg
Force of pull = 70N
Frictional force = 20N
Unknown:
Acceleration of the wagon = ?
Solution:
Frictional force is a force that opposes motion.
The net force is given as:
Net force = mass x acceleration
Force of pull - Frictional force = mass x acceleration
Insert the parameters and solve;
70 - 20 = 10 x acceleration
50 = 10 x acceleration
Acceleration = 5m/s²
Wonderwoman, from rest, runs until reaching m her flight takeoff speed of 15 to the west. A S graph of her acceleration over time is shown below, where eastward is the positive acceleration direction. Which graph shows her velocity over time?
Answer:it’s the graph starts on the origin but is going down
Explanation: khan academy
A car accelerates from rest at a rate of 3 m/s² for 4 seconds. How far did the car travel?
PLEASE HELP fast
Which of the following statements does NOT apply to Newton’s second Law of Motion? *
5 points
a. The more mass something has, the more force it would take to accelerate it.
b. The more force applied to an object’s mass, the more it will accelerate.
c. The force required to accelerate an object equals the objects mass times it’s acceleration.
d. Objects of the same size will accelerate equally if they have different forces applied to them.
Answer:
d
Explanation:
it is never stated in science
Objects of the same size will accelerate equally if they have different forces applied to them. This statement (D) does NOT apply to Newton’s second Law of Motion.
What is Newton's second Law of Motion?Newton’s second law of motion states that “Force is equal to the rate of change of momentum. For a constant mass, force equals mass times acceleration.
As momentum is product of mass and velocity, the more mass something has, the more force it would take to accelerate it. So option (A) is correct.
As rate of change of momentum of a body refers product of mass and acceleration of a body, the more force applied to an object’s mass, the more it will accelerate and the force required to accelerate an object equals the objects mass times it’s acceleration. So, option (B) and (C) is correct.
But force has no direct elation with size of the body. So, option (D) is not correct.
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Why did scientists gather at Los Alamos in 1945?
Answer:
Oppenheimer suggested that the bomb laboratory operate secretly in an isolated area but allow free exchange of ideas among the scientists on the staff.
Explanation:
How old was Antoine Lavoisier's wife when they married
jsjshebsjsusunxndj 78
A girl throws a pebble into a deep well at 4.0 m/s (downward). It hits the water in 2.0 s. How far below the ground is the water's surface? What is the pebble's average velocity?
Answer:
27.6 m13.8 m/sExplanation:
(b) The initial velocity is added to that due to acceleration by gravity. The velocity is increased linearly by gravity at the rate of 9.8 m/s². The average velocity of the pebble will be its velocity halfway through the 2-second time period.* That is, it will be ...
4 m/s + (9.8 m/s²)(2 s)/2 = 13.8 m/s . . . . average velocity
__
(a) The distance covered in 2 seconds at an average velocity of 13.8 m/s is ...
d = vt
d = (13.8 m/s)(2 s) = 27.6 m
The water is about 27.6 m below ground.
_____
* We have chosen to make use of the fact that the velocity curve is linear, so the average velocity is half the sum of initial and final velocities:
vAvg = (vInit + vFinal)/2 = (vInit + (vInit +at))/2 = vInit +at/2
__
If you work this in a straightforward way, you would find distance as the integral of velocity, then find average velocity from the distance and time.
[tex]\displaystyle d=\int_0^t{(v_0+at)}\,dt=v_0t+\dfrac{1}{2}at^2=t\left(v_0+a\dfrac{t}{2}\right)\\\\v_{avg}=\dfrac{d}{t}=v_0+a\dfrac{t}{2}\qquad\text{the formula we started with}[/tex]
A)What is the acceleration at 1 second?
Answer in units of m/s 2.
B) What is the velocity at 2 seconds?
Answer in units of m/s.
C) What is the position at 2 seconds?
Answer in units of m
Jill is pulling a 200. Newton sled through the snow at constant velocity using a horizontal force of 10. Newtons. What is the kinetic coefficient of friction of the sled on the snow?
Answer:
The kinetic coefficient of friction of the sled on the snow is 0.05
Explanation:
The given parameters are;
The weight of the sled Jill is pulling, W = 200 N
The force with which Jill is pulling the the sled = 10 Newtons
The nature of the speed with which the sled is pulled = Constant speed
Therefore, given that the only opposing force to the pulling of the sled = The force of kinetic friction, we have;
The force with which Jill is pulling the the sled = 10 Newtons = The force of kinetic friction, [tex]F_k[/tex]
The force of kinetic friction = The weight of the sled, W × The kinetic coefficient of friction of the sled on the snow, [tex]\mu _k[/tex]
[tex]F_k[/tex] = W × [tex]\mu _k[/tex]
[tex]\mu _k[/tex] = [tex]F_k[/tex]/W = 10 N/(200 N) = 0.05
The kinetic coefficient of friction of the sled on the snow = [tex]\mu _k[/tex] = 0.05.
Can someone please help
Answer:
k nishant
Explanation:
the answer is option B
What is the difference between abiotic and biotic factors?
Answer:
Abiotic referfers to non-living and biotic factors are living or once living
Explanation:
in number one is Mirna is pregnant and must consult a medical professional, What kind of doctor should she seek?
guys plss help me
plss answers all i needed the answer
Which would be least likely to completely dissolve in water?
o hydrochloric acid
sulfuric acid
O nitric acid
O acetic acid
Answer:
nitric acid
Explanation:
because it is a solvent
Answer:
acetic acid
Explanation:
Not sure but I think so :) hope its right and helps